The question suffers from a few problems:
Problem #1:
The closer we read the question, the less sense it makes. What is 0.25 miles apart ?
The pieces of the field ? The fence-posts ? Nothing we can think of seems like a reasonable
assumption. So you know what ? We're just going to ignore that part of the question,
and talk about the length of Fencing you'll need.
Problem #2:
The area doesn't tell you the perimeter. Your 25 acres could have an infinite
number of different shapes and sizes, and every one of them would take a
different amount of fencing to enclose it.
If you want to use the absolute minimum amount of fence, then you want the
25 acres in the shape of a circular field, 392.5 yards in diameter. Then the
circumference of the circle is 3,700 ft. = 1,233.1yards. (rounded)
If you definitely want straight sides around the plot, then you want it in the
shape of a square with sides of 347.9 yards. The perimeter of the square is
4174.2 ft = 1,391.4 yards. (rounded)
That's the minimum. If it's a rectangle and not square, then the longer and
skinnier it is, the more fence it needs ... while keeping the same constant area
of 25 acres. For example:
-- If it's 242 yds by 500 yds, it's 25 acres, and you need 1,484 yards of fence to enclose it.
-- If it's 121 by 1,000 yds, it's still 25 acres, but you need 2,242 yards of fence to enclose it.
-- If it's 44 by 2,750 yds, it's still 25 acres, but you need 5,588 yards to enclose it.
1000
It depends on what shape the one acre is, and what kind of fence is to be installed. For example, a simple livestock fence consisting of woven wire and a three-strand barbed wire on top, and assuming the acre is square will require 835 feet of woven wire, 2,500 feet of barbed wire, 12 corner posts, and about 70 steel T-posts. Different shapes of field will change this, and different types of fencing require different materials.
the sides of the fence are parallel to the rows of crops.
240
The perimeter is the border or outer boundary around a two dimensional figure and is the length of such a boundary - a field for example, a perimeter fence
i dont no
Perimeter of field = 2*(250+300) = 2*550 = 1150 feet. Therefore, number of post required = 1150/5 = 230 posts.
1000
The length of a standard baseball field is approximately 90-95 meters (300-330 feet) from home plate to the outfield fence.
It depends on the spacing of the posts and the shape of the field to be fenced in.If the field is 1 meter by 4800 meters and the posts placed 2 1/2 meters apart then you will need 3840 posts.If the field is circular and the posts placed 2 1/2 meters apart then you will need 98 or 99 posts.If the field is square and the posts placed 2 1/2 meters apart then you will need 108 posts.Any shaped field, therefore, will have between 98 and 3840 posts needed to fence it in. as the perimeter will be at least 245 meters for a circular field and as much as 9602 meters for a 1 meter wide field (assuming no part of the field is less than 1 square meter). All other possibilities will fall in between these two extremes.Note: by increasing or decreasing the distance between posts the number of posts will decrease or increase accordingly.
It depends on what shape the one acre is, and what kind of fence is to be installed. For example, a simple livestock fence consisting of woven wire and a three-strand barbed wire on top, and assuming the acre is square will require 835 feet of woven wire, 2,500 feet of barbed wire, 12 corner posts, and about 70 steel T-posts. Different shapes of field will change this, and different types of fencing require different materials.
The perimeter of the rectangular field is 2*(L+W) = 2*(120+50) = 2*170 = 340 feet
335 feet
The out of bounds line runs around a football field but never moves.
So you are looking to find the perimeter of the square. Since the area of the square is 118.81 m2, then the perimeter is 4(√(118.81 m2) = 43.6 m.
Ivy
325 feet