That means that total momentum doesn't change. It is the same before and after the collision.
There is a Law of Conservation of Momentum, which states that total momentum is always conserved. In this case, that means that - assuming no additional bodies are involved - the total momentum before the collision will be the same as the total momentum after the collision. It doesn't even matter whether the collision is elastic or not.
False - the thing to remember is that momentum is conserved.
In an elastic collision, no kinetic energy is lost, and the relative speed of separation of the objects after the collision is the same as the relative speed before the collision. In an inelastic collision, part of the elastic energy is lost, and the relative speed after the collision is less.
Momentum like mass will always be conserved in any process. Momentum is the product of mass and velocity of the object. It is symbolically denoted as p=m*v where p = momentum, m = mass and v = velocity
The momentum of the two lumps of clay are the same since the momentum is the same before and after the collision. The kinetic energy is not conserved but transformed into gravitational potential energy (GPE) since the position of motion has changed. *Keep in mind: KE is the energy of motion. GPE is the energy that something posses due to its position. :)
1 +/- two decimal place
There is a Law of Conservation of Momentum, which states that total momentum is always conserved. In this case, that means that - assuming no additional bodies are involved - the total momentum before the collision will be the same as the total momentum after the collision. It doesn't even matter whether the collision is elastic or not.
False - the thing to remember is that momentum is conserved.
well i know momentum remains same before and after collision... But what about the period during which collision takes place?
In an elastic collision, no kinetic energy is lost, and the relative speed of separation of the objects after the collision is the same as the relative speed before the collision. In an inelastic collision, part of the elastic energy is lost, and the relative speed after the collision is less.
Completely If you add all the energy of all the resultants of the collision together, you will arrive at the same value as the sum of the energies of all the components before the collision.
No. Newton's first law of motion states that the momentum of a system is conserved as long as there's no external force being applied on the system.
Hi, in line with Newton's laws of motion the momentum before and after a collision is always conserved (when no external force is applied to change the systems momentum). In elastic collisions we can apply the conservation of momentum and conservation of energy principles. In inelastic collisions we can only apply the conservation of momentum principle. Energy is not conserved in inelastic collisions because energy is lost through small deformations, noise, friction, etc. We can compute the coefficient of restitution that helps determine this degree of energy loss from impulse-momentum equations.
Momentum like mass will always be conserved in any process. Momentum is the product of mass and velocity of the object. It is symbolically denoted as p=m*v where p = momentum, m = mass and v = velocity
The momentum of the two lumps of clay are the same since the momentum is the same before and after the collision. The kinetic energy is not conserved but transformed into gravitational potential energy (GPE) since the position of motion has changed. *Keep in mind: KE is the energy of motion. GPE is the energy that something posses due to its position. :)
conservation of momentum
The total momentum before the collision is the same as the total momentum after the collision. This is known as "conservation of momentum".