Its more about water volume and filter area. We have a 100,000 gallon pool that uses 180 square feet of filter area - these consume 25 pounds of DE every time we backflush and recharge the filters.
Assuming your pool is 5 feet deep on average you only have 3000 cubic feet of water which is about 23,000 gallons. So you would need roughly 6 or 7 pounds of DE. Of course if your pool has more water then you need more DE. Your filter manufacturers should tell you how much DE you need.
it depends on the size of your filter, but i stopped using de and went to fiberclear, you us so much less and its non toxic. 2 bags will last us all summer for our inground pool.
A 28-foot round pool filled with 4 feet of water would contain about 18,500 gallons.
About 18,402 gallons.
20000
28 is the diameter of the pool and 4 is the height (depth). 1 cubic foot is approx. 7.48 gallons. A round swimming pool is a cylinder. So: pi x (28/2)2 x 4 = 2463 cubic feet, multiply by 7.48 = 18423.24 gallons
I do not have any water in your pool. You may have some but not me!
That all depends on how deep the water has to be, which the question neglects to specify.
28 or 30 mil
To calculate the volume in gallons of a round pool, do the following calculation: diameter x diameter x depth x 5.9 Example: 28ft x 28ft x 4ft x 5.9 = 18,502.4 gallons
3.14 x28 x 28 /4 x 4 x 7.48gals/ cu ct = 18, 400 gallons
This pool can hold a maximum of about 18,420 gallons of water.
If the pool is 28 feet wide, you'd have to walk around the outside 60 times to equal one mile of distance.
It depends on how deep you fill the pool. So, let's take the most common depths for a 33-foot round pool; 3, 4 and 5 feet:For 3 feet of water the total gallons will be about 19,275.For 4 feet of water the total gallons will be about 25,700.For 5 feet of water the total gallons will be about 32,125.