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growing rice required much labor,so the demand for slaves increased.
In general Muskets were still the go to weapon.Rifles were more accurate and could shoot further, but required much maintenance and required a much longer reload period.
Advantages: -make work much more easier to complete -make work faster to complete -less energy required -less exerted force required Disadvantages: -may malfunction and corrupt the entire system
The success of the national government required the support of the propertied classes
Not like we have today, but yes, they did have basic analog targeting systems that allowed certain data to be fed in to get a targeting solution. They also used handheld calculators (much like a slide rule) and plots to determine the target track. Knowing how to do it the old way by hand is still required today for modern submariners, in case main targeting systems fail.
64ml of nitric acid required fr one litre
0.056g
40mn
0.745*0.5 g
The formula weight is 121.5 --> this is equivalent to 1M with 121.5g tris in 1L dH20. For a 5M stock, use 5x as much tris in the same 1L dh20.607.5 g tris into 800ml dH2O - stirring - then pH to 7.5 with 6M HCl and QS to your final volume of 1L
Tris(hydroxymethyl)aminomethane (Tris) has a molecular weight of 121.14 g/mol. 50 mM = 0.050 mol/L (x 121.14 g/mol) = 6.057 g/L To prepare a 1L solution first weigh out 6.057 g Tris Add roughly 70% of final volume of water (i.e. 700 mL) Use a pH-meter to measure the pH of the solution Lower the pH of the solution to 7.2 using undiluted HCl Use a measuring cylinder or volumetric flask to make the volume up to 1000 mL If you add too much HCl you need to add more Tris and then recalculate the amount of water that you need add. In this case, every 1 g of Tris requires 165 mL of water to be added.
1 and a half times
The concentration of a solution is some measurement of how much solute there is in the solution.
The concentration of a solution is some measurement of how much solute there is in the solution.
The concentration of a solution is some measurement of how much solute there is in the solution.
RMM of CuSo4 . 5H2O = 160 + 5x18 = 250 g How much contain gram in 100 mL of 0.050 M CuSO4 solution is - Solution: = 0.050 x 100/1000 x 250 = 0.050x4 (100)/ 16 = 1.25 g
To determine the concentration of a solution, you would need to separate the solution. You then determine how much of the solution is diluted, and how much is whole.