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800 kj
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How much energy is required to melt 2 kg of aluminum Use the table below and this equation Q mLfusion?
Using the specific latent heat of fusion for aluminum (397 kJ/kg), we can calculate the energy required to melt 2 kg of aluminum: Q = m * L Q = 2 kg * 397 kJ/kg Q = 794 kJ Therefore, it would require 794 kJ of energy to melt 2 kg of aluminum.
How much energy is needed to melt 2 kg of aluminum?
800kj-----------Apex<('-'<)
How much energy is required to vaporize 2 kg if aluminum?
To calculate the energy required to vaporize 2 kg of aluminum, we use the heat of vaporization of aluminum, which is approximately 10,900 J/kg. Therefore, the energy required is 2 kg × 10,900 J/kg = 21,800 J, or 21.8 kJ. This is the amount of energy needed to convert 2 kg of aluminum from a liquid to a vapor at its boiling point.
How much energy is required to vaporize 1.5 kg of aluminum (refer to table of latent heat values.)?
To calculate the energy required to vaporize 1.5 kg of aluminum, we need to use the latent heat of vaporization for aluminum, which is approximately 10,900 J/kg. The energy required can be calculated using the formula: Energy = mass × latent heat of vaporization. Thus, for 1.5 kg of aluminum: Energy = 1.5 kg × 10,900 J/kg = 16,350 J. Therefore, 16,350 joules of energy is required to vaporize 1.5 kg of aluminum.
How much energy of is required to vaporize 1.5 kg of aluminum?
1650kj
How much energy is required to melt to kilograms of copper?
The energy required to melt 1 kg of copper at its melting point of about 1084°C is approximately 205 kJ. Therefore, to melt 2 kg of copper, you would need around 410 kJ of energy.
How much energy is required to melt 1.5 kg of gold?
The heat of fusion for gold is 64.4 kJ/mol. To convert this to energy required to melt 1.5 kg of gold, we need to calculate the number of moles in 1.5 kg of gold (1.5 kg of gold is approximately 0.047 moles). Then, the energy required would be approximately 3.03 kJ.
How much energy is required to melt 2kg of gold?
To melt 2 kg of gold, it would require approximately 66,190 Joules per gram. Therefore, for 2 kg of gold, the total energy required would be around 132,380,000 Joules.
How much energy is needed to vaporize 2 kg of aluminum?
To vaporize aluminum, you need to consider its heat of vaporization, which is approximately 10,700 kJ/kg. For 2 kg of aluminum, the total energy required would be 2 kg × 10,700 kJ/kg, equating to about 21,400 kJ. Therefore, around 21.4 million joules of energy is needed to vaporize 2 kg of aluminum.
How much energy is required to vaporize 1.5 kg of aluminum apex answer.com?
The energy required to vaporize 1.5 kg of aluminum can be calculated using the formula: energy = mass * heat of vaporization. The heat of vaporization for aluminum is around 10,000 J/g. So, the energy required would be 1.5 kg * 10,000 J/g = 15,000,000 J or 15,000 kJ.
How much energy is required to vaporize 2kg of aluminum?
To vaporize aluminum, you need to consider its heat of vaporization, which is approximately 10.5 MJ/kg. For 2 kg of aluminum, the energy required would be about 21 MJ (megajoules). This calculation assumes that the aluminum is already at its melting point and that no heat losses occur during the process.
How much heat is required to vaporize 2 kg of aluminum?
To vaporize aluminum, you need to know its heat of vaporization, which is approximately 10,700 kJ/kg. Therefore, to vaporize 2 kg of aluminum, you would require about 21,400 kJ (2 kg × 10,700 kJ/kg). This calculation assumes that the aluminum is already at its melting point and that the vaporization occurs under standard atmospheric conditions.
