2 1/2 g
5g would remain
The mass is 1,075 g.
I suppose that you think to the radioactive isotope Cs-17; After 4 years remain 9,122 g.
2 1/2 g
1mg. If the half life is 24 minutes then in 48 minutes the sample would decay twice. After one half life the mass would halve (to 2mg) and after the second it would have again (to 1mg).
2 1/2 g
2 1/2 g
5g would remain
Peat would remain largely unconsolidated. Mudstone is a rock.
1mg
0.5 mg
The mass is 1,075 g.
.25 mg
I suppose that you think to the radioactive isotope Cs-17; After 4 years remain 9,122 g.
The mass is 1,075 g.
75
You must know the half life of Caesium to calculate this.