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The half life for Cu=64 is 12.7 hours. Thus, 12 hours represents 12/12.7 = 0.945 half lives.
Fraction remaining = 0.5^0.945 = 0.519 remaining
2 mg x 0.519 = 1.04 mg remaining

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7y ago
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Q: How much cu-64 would remain after half-life from a 2mg sample after 12 hours?
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