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Depends on the wattage of the bulb. Formula is Power (watts) = Voltage * Current (A). Therefore for a 55w bulb, in a 12V car, bulb draws 4.6Amps.
Basically, Power = Current*Voltage Current = Power/Voltage Current = 15/120 Current = 0.125A or 125mA
The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
To find the resistance necessary, one would need to know how much current the bulb draws. If one knows the current the bulb draws, then one would subtract the 14 volts from 120 volts then divide that by the current the bulb draws and one will find the resistance needed. Once this has been done, one would need to multiply the current drawn by the voltage drop to get the wattage rating necessary. Another important detail to note is that the power dissipated by the resistor will be much greater than the power consumed by the bulb itself. Finally if the bulb burns out the voltage across the contacts will be 120V. I would not recommend using this method to drop the voltage for the bulb.
The filament of a light bulb overs enough resistance to current flow, that the filament heats up so much that it will glow and produce visible light.
If the current is stronger then the bulb will be brighter.The reading is much easier when you sit under the brighter bulb.
Too much current for the rating of the bulb.
That does not depend directly on the brightness of the bulb, it depends on the current drawn by the bulb (which depends on the efficiency of the bulb). For example an incandescent bulb will draw much more current than a much brighter CFL bulb or LED bulb. Therefor switching to an brighter LED bulb can make the battery last much longer while switching to a brighter incandescent bulb will make the battery run down quicker.
Ohm's law applies: Current = Voltage / Resistance As such if you double the resistance of the light bulb you end up with half as much current.
how much resistance does a light bulb creat if iyt has a current of 25 mA around it in a 9 V circuit?
The current of one bulb (two bulbs shorted) would be about1 three times the current of three bulbs.1 I say "about" because resistance is a function of temperature, and running three times the current through one bulb will make that one bulb much hotter, increasing its resistance. It might also burn out the bulb.
same current flow in each bulb
To answer this question a voltage must be given.
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Depends on the wattage of the bulb. Formula is Power (watts) = Voltage * Current (A). Therefore for a 55w bulb, in a 12V car, bulb draws 4.6Amps.
50-Voltage
A 240 v 14 w cfl bulb uses about 0.14 amps.