Everything Depends on the voltage supply ......
Current flow (Amp) = Watt / Voltage
the Current flow will be 1 amp if voltage is 1 V
the Current flow will be 0.5 amp if voltage is 2 V
the Current flow will be 0.25 amp if voltage is 4 V
and so on.......
The current flowing through a bulb is equal to the (voltage across the bulb) divided by the (bulb resistance), and can be expressed in Amperes. The rate at which the bulb dissipates energy is equal to (voltage across the bulb) times (current through the bulb), and can be expressed in watts.
Amps ain't nothing really until you cut on a light switch in your house. It's a term of electricity measurement of which is being used in a circuit. Say you have an unlit 50 watt light bulb in your den plugged into the 110 volt outlet. The 110 volts is there ready to operate the lamp. Cut it on and the electron flow is called current. Replace the bulb with a 100 watt bulb and the current flow will double. Cut off all the lights and the power meter on your house will run slower and you use less current and will have a lower electric bill next month.
Watt
A 100 watt 220 volt light bulb (or anything consuming 100 watts on 220 volts) draws 100/220, or .45 Amps. It will also have about 220²/100, or 484 ohms resistance. A 60 watt 220 volt light bulb (or anything consuming 60 watts on 220 volts) draws 60/220, or .27 Amps. It will also have about 220²/60, or 807 ohms resistance.
If this is a homework assignment, please consider trying to answer it yourself first, otherwise the value of the reinforcement of the lesson offered by the assignment will be lost on you.If a 100-watt bulb draws 0.87 amperes of current, 17 of them will draw about 14.8 amperes, (0.87 times 17), if they were wired in parallel.However, wiring them in series would not give you 0.051 amperes, (0.87 divided by 17), as one might expect, because the resistance-temperature coefficient of bulbs is quite dramatic, so more current would actually be drawn because the bulbs would be much cooler. How much more would require testing. You could do this by supplying 6.8 volts to one bulb and seeing what you get, or just hook 17 of them up in series to 115V.
The current flowing through a bulb is equal to the (voltage across the bulb) divided by the (bulb resistance), and can be expressed in Amperes. The rate at which the bulb dissipates energy is equal to (voltage across the bulb) times (current through the bulb), and can be expressed in watts.
To answer this question a voltage must be given.
current consumtion of a bulb
A 60 watt bulb at 12 volts will pull 5 amps of current.
A 240 v 14 w cfl bulb uses about 0.14 amps.
watt
It's 75/120 and the answer is in amps.
A 50 watt bulb designed to run on 12 volts takes 4.17 amps. A 50 watt bulb designed to run on 230 volts takes 0.217 amps.
As long as the lamp holder will take the larger wattage lamp and the current of the circuit is sized to take the larger current then yes, the lamps should be interchangeable.
You can get a 65-watt alternator to generate the current, or alternatively it can be bought from the electricity supply company in many locations.
Almost twice as much as 100 is almost twice 60.
More than I want to calculate for you right now. Also the number is the same whether the bulb is lit (current flowing) or dark (no current flowing). Also tungsten has 74 electrons, of which only 2 are in the conduction band and free to participate in current flow.