The formula you are looking for is I = W/E. Amps = Watts/Volts.
V = I * R. 1.5 = 8*IThe current flow is 3/16 Amps.
It produces heat/light
a test lamp i literrally a bulb connected to two wires. it was used to check if you had any current or voltage in a circuit. you would just take the build with the two wires and touch it with the curcuit. if the bulb lights up means that you have a complete circuit if not it means that the curcuit is working. The test lamp is like a medival tool to a multimeter
The current flowing through a bulb is equal to the (voltage across the bulb) divided by the (bulb resistance), and can be expressed in Amperes. The rate at which the bulb dissipates energy is equal to (voltage across the bulb) times (current through the bulb), and can be expressed in watts.
The electrical current comes into the bulb from the metal side,flow through the filament ,and out the tip.
The bulb glows dimly when current is passed through a vinegar solution because the small number of ions in the vinegar solution move through the filament of the bulb.
no
The things you need for your curcuit are: A light bulb, Bell wire, A Battery and a conducter ex. pin, paper clip Attach the bulb together with the battery using the bell wire. With the two ends of the wire connect to the conducter and see if light bulb comes on.
The current of one bulb (two bulbs shorted) would be about1 three times the current of three bulbs.1 I say "about" because resistance is a function of temperature, and running three times the current through one bulb will make that one bulb much hotter, increasing its resistance. It might also burn out the bulb.
No. A light bulb is a bulb that contains a filament that gets hot when electric current is passed through it.
When you have a light bulb in front of each other (all connected to wires to a battery)
No. A light bulb is a bulb that contains a filament that gets hot when electric current is passed through it.