that depends on th type of sand
About 41 pounds.
Sand needed: 8*6*1.5 = 72 cubic feet
Volume of sand required = 7 ft * 7 ft * 1/6 ft = 49/6 cubic feet = 8.166... cubic ft.
137.5 cubic feet or 5.09 cubic yards.
The answer depends on the grain size, lithology, moisture content, and level of compaction of the sand. Generally, one cubic ft of clean (no silt/clay), dry, fine to medium sand that has been compacted to a dense, non-yielding condition will weigh about 110 lbs., while a loose fine to medium sand will weigh about 100 lbs. per cubic foot.
270-ft x 1/2-ft = 135 cubic ft = 5.0 cubic yards
12 ft * 10 ft * 10/12 ft = 10 cubic feet.12 ft * 10 ft * 10/12 ft = 10 cubic feet.12 ft * 10 ft * 10/12 ft = 10 cubic feet.12 ft * 10 ft * 10/12 ft = 10 cubic feet.
The answer will depend on how thinly the sand is spread.
This is a volume calculation. I assume the dimension for the "6" is inches? If so, the volume= 20x20x0.5= 200 cubic ft.= 7.4 cubic yards
Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.
That would take 250 cubic meters of sand to fill as 10*5*5 is 250.
8ft Wide by 8ft Long by 1ft Deep is 64sq/ft. A yard of sand is 36sq/ft. You will need a little less than 2sq/yards (72sq/ft). -------------------------------------------------------- We're talking about volume, not area, so 8x8x1 = 64 cubic feet, not sq. ft. A "yard" of sand actually means a cubic yard and is 3ft x 3ft x 3ft = 27 cubic feet, not 36 sq/ft. So you need 64/27 or a little over 2 1/3 cubic yards of sand.