well the Pizza with one topping is about 15 dollars candian so if two then maybe 16.50 i think so not so sure though so yeah
about .75 cents about .75 cents
2*2*2*2 = 16, counting one with no toppings.
· zesty
32 combinations. 4 of these will have no toppings, or all three toppings, 12 will have one topping and another 12 will have 2 toppings.
10
You can find Pizza Hut coupons at Retail Me Not. Some of the coupons offered are - Any Pizza (any size, any toppings) $9.00, a Dinner Box for $10.00, or 2 Medium Pizza with any toppings $8.00.
120 5 x 4 x 3 x 2 x1 = Toppings 20 x 6 x 1 = Toppings 120 x 1 = Toppings 120 = Topping Combinations
A standard large pizza from Snappy costs $11, and comes with 2 toppings. Some specialty pizza deals can run up to $14. "The Beast", which is about the size of 3 large pizzas, goes for around $25.
you can put as much toppings as you want but mostly theirs cupcakes with 2 toppings
well, you can to topping 1&2, topping 2&3, topping 1&3, topping 1, 2 and 3, and you can also do all three toppings. so that's seven different types for one size pizza, and you can have all combinations in four sizes. that makes a total of 28 different pizza combinations.
8 over 3, which is the same as (8 x 7 x 6) / (1 x 2 x 3).
I have no idea ithink max. 1kg
If you must use all 5 with no repetition, you can make only one pizza. 5C5, the last entry on the 5 row of Pascal's triangle. If you can choose as many toppings as you want, all the way down to none (cheese pizza), then you have 5C0 + 5C1 + 5C2 + 5C3 + 5C4 + 5C5 = 32. Another way to think about it is no toppings would allow one pizza (cheese), one topping would allow two pizzas (cheese, pepperoni), two toppings would allow four pizzas, three toppings would allow eight pizzas, four toppings would allow sixteen, creating an exponential pattern. p = 2 ^ t. So, 10 toppings would permit 1024 different combinations