3.72kwh * per unit charge,e.g if per unit charge is Rs 7 then the cost 3.72*7=26.04.
(700 watts) x (10 hours/day) x (30 days/month) x (1 kilowatt / 1,000 watts) =(700 x 10 x 30 / 1,000) (watt - hour - day - kilowatt / day - month - watt) =210 kilowatt-hour / monthWe're guessing that the actual cost of your electric energy is $0.09 per kilowatt-hour.(210 kilowatt-hour / month) x ($0.09 / kilowatt-hour) = $18.90 per month .
* 0.4A * (voltage of device V) = Power in watts P1 * P1/1000 = Power in kW P2 * P2 * (electric rate in dollars per kWhr) = Cost dollars/hr C * C * (days in this month) * 24 hr/day = Cost in dollars for this month
20 Watts x 24 hours x (days in month) so 31 = 14880 wh 14880/1000 = 14.88kwh
Assuming an average charge or 18 cents ($US) per kilowatt hour you would pay roughly $4.32 (#US) a day or $130 ($US) a month. This is figured by taking 24 hours and multiplying by 1 KW(1000 watts) to get 24 KWH per day, then multiply by 30 to get 720 KWH per month. Then multiply this by the current electric rate for a daily or monthly amount. Refer to the below formulas if you wish to change any of the above variables.Formula for finding power cost over a number of days.(24*Number of Days) * (Watts used/1000) = KWH usedthen(KWH used) * (cost of electric per KWH) = Total costFormula for finding power cost over a number of hours.(number of hours) * (Watts used/1000) = KWH usedthen(KWH used) * (cost of electric per KWH) = Total cost
-9900
60 (watts) x 12 (hours on) x 30 (days per month) = 21600 (watt-hours) 21600 / 1000 = 21.6 killowatt hours X your electric providers price = $$$
Convert the watts to kilowatts, and the days to hours. Then multiply kilowatts x hours to get kWh.
At 10 cents per kWh (Kilowatt hour), one 100 watt incandescent light bulb ran for 24 hours straight will cost 24 cents a day. $7.30 a month, $87.60 a year. kWh = (Watts Used * Hours per Day * Days per Month) / 1000 Cost per Month = kWh * Cost per kWh
A simple electrical device is a 60 watt light bulb. The bulb is consuming 60 watts of electricity from the moment you turn it on. If you keep that light bulb on for 10 hours the power used is 60 watts x 10 hours = 600 watts of power. Electricity is sold in Kilowatt Hours. A Kilowatt is 1000 watts of power. Depending on the state you live in, it sells for 7 to 18 cents per Kilowatt Hour. So if you leave that light bulb on 10 hours per day for 30 days you will have used up 600 watts x 30 days = 18,000 watts of electricity = 18 Kilowatt Hours. At an average cost of 10 cents per Kilowatt Hour that bulb costs you $1.80 per month to leave on. The formula is watts x time x cost per Kilowatt Hour = cost of use...Answer provided by Gene Evangelist
The simple way to calculate cost is $1 per watt per year. This is based on a cost of about 11 cents per kilowatt hour. Your cost may vary. So, 60 watts times 1/2 year (12 hours /day) divided by 12 ( 1 month) equals $2.50 per month.
(700 watts) x (10 hours/day) x (30 days/month) x (1 kilowatt / 1,000 watts) =(700 x 10 x 30 / 1,000) (watt - hour - day - kilowatt / day - month - watt) =210 kilowatt-hour / monthWe're guessing that the actual cost of your electric energy is $0.09 per kilowatt-hour.(210 kilowatt-hour / month) x ($0.09 / kilowatt-hour) = $18.90 per month .
That will depend on the month. In a month with 31 days, there are 744 hours. In a month with 30 days, there are 720 hours. In a leap year February, with 29 days, there are 696 hours. In a normal year February, with 28 days, there are 672 hours.
Note that a day is 24 hours. Then... 0.7 days a month is around 16.8 hours a month.
24 hours= 1 day 31 days = 1 month 24 x 31 = if your month is 31 days
* 0.4A * (voltage of device V) = Power in watts P1 * P1/1000 = Power in kW P2 * P2 * (electric rate in dollars per kWhr) = Cost dollars/hr C * C * (days in this month) * 24 hr/day = Cost in dollars for this month
Depends how many days in the month. 120 / number of days = hours per day eg 30 days in the month: 120 / 30 = 4 hours per day
It depends which month if it is a month with 31 days then 744 hours. hope that helps=)