100 litres warmed from 10 to 45 degrees C requires 35x100000 calories. There are 4.2 Joules per calorie so that is 14.7 MJ of energy, in other words 4 units (kWh).
The tank would also need to be heated which might take an extra ½ unit, so a
3 kW immersion heater would need to run for 1½ hours.
It depends on what you mean by militer. It is not a recognised measure of volume.
A liter is, by definition, one cubic decimeter.
292 kj
.001 liters in a centiliter .01
100$ 920 kw hours per month
The answer depends on your usage. If, typically you use less than 100 litres then the smaller geyser is more efficient because you are not heating up extra water.
100 centiliters to the liter.
1/10 of a liter 0.1 liter
1/10 of a liter 0.1 liter
1 liter = 100 cl 1 cl = 0.01 Liter
100 cl = 1 liter ⇒ 60 cl = 60 ÷ 100 liter = 0.6 liters
0.15 L 1 liter = 100 centiliters 1 centiliter = 0.01 liter
1/100 liter is 10 mL (1 liter = 1,000 mL).
$100-$300
That is 1/10 th of a litre
About 100 to 150
7L x 100cL/1L = 700cL