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The current through a 220 volt 150 watt bulb is I = W/E = .68 amps.

The resistance of that bulb is R = E/I = 324 ohms.

The wattage used by the 220 volt bulb when 110 volts is applied W = E(sqd)/R = 37 watts.

Half the voltage with the same resistance will quarter the wattage output.

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