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It depends on the temperature of the water that you begin with.
But lets say that you start with 100 Kg of water at 100'C.
the heat of vapourization of water is 2260 J /g or 2,260,000 J/Kg
Since we have 100Kg it would require 226,000,000 J
converting Joules into Kilowatt hours gives
226 MegaJoules
as 1 kilowatt hour is equal to 3.6 megajoules
226/3.6 =62.77 kilowatt hours
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∙ 12y ago
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