This question cannot be answered as currently posed for three reasons:
The initial temperature is not specified
The material being heat up is not specified
kWatts is a unit of power, not energy.
It is also not clear how much of the mystery substance is involved or what phase it is in. It seems likely that the intention was to ask about heating 4000 liters of something, but the abbreviation for liters is not "lt".
q = m x C x ΔT
q = amount of heat energy gained or lost by substance in Joules (J)
m = mass of sample in grams = 5000g
C = heat capacity (J/ g•oC) = 4.181 J/g•oC for water
Tf = final temperature = 60 oC
Ti = initial temperature = 20 oC
ΔT = change in temperature = (Tf - Ti) = 60 oC - 20 oC = 40 oC
q = 5000 g x 4.181 J/g•oC x 40 oC = 836200 J
Water specific value = 4,16 kJ/kg*degree The increace in temperature = 60 - 4 = 56 The amount of water = 4 liters = 4 kg Energy recuired = 932 KJ = 932 KJ/3600 KJ/kWh = 0,259 kWh
It takes 100 calories to heat water by one degree.
30
Temperature is the measure of how much heat energy something has. Just like distance is the measure of how far apart two points are. 0 degrees centigrade for example is the point at which water freezes whereas 100 degrees is the boiling point of water. So a warm bath tub may have a lower temperature than a candle flame, but it has more heat energy stored in it overall because it would take a lot of candles to heat up a bath tub.
2500
A watt is a measure of energy, which may or may not be heat, but heat is considered to be the simplest form of energy and is an easy way to compare amounts of energy. Another measure of energy that is easy to work with is a calorie, which is the amount of energy needed to raise the temperature of 1 gram of water by 1 degree C. In these terms without special conditions, this applies only between 0 and 100 degrees C, because freezing and boiling make the equations much more complicated. A watt is approximately 86 calories, meaning that applied to a gram of water would raise its temperature by 86 degrees centigrade. A kilowatt is 1000 watts meaning that it could raise the temperature of that gram of water by 86000 degrees--at least theoretically, but that image is all but useless. So let's say that a kilowatt represents enough heat to raise the temperature of a liter (1000 g) of water by 86 degrees C.
Ok, lets assume that a pool of water and the air are at the same temperature. There are a number of ways you can lose heat to the surroundings, however in this example the most important reason is: Conduction. This is due to direct contact with surrounding particles. As the Particles in you body vibrate with energy they collide with surrounding air or water particles. You will thus lose much more energy to water than to air as water is much better at conducting heat away from you. (There are many times more water particles to transfer the energy away). In terms of heat capacity, if water has a higher heat capacity then it will take more energy from your body to heat it up. Seeing as you body is warmer than the surrounding water, the water will take more of your thermal energy to reach thermal equilibrium with you.
Heat is defined as the total kinetic energy of all the atoms and molecules that make up a substance.Temperature is a measure of the average kinetic energy of the individual atoms or molecules in a substance.
It has a much higher volume of water compared to the tea cup. It takes less energy to heat a small amount of liquid such as a tea cup.
Specific heat capacity tells you how much stuff energy can store. specific heat capacity is the amount of energy needed to raise the temperature of 1kg of a substance by 1 degrees celsius. water has a specific heat capacity of 4200 J/kg degrees celsius.
19.7 kJ
1.3 kg water = 1300 grams. q(Joules-heat energy) = mass * specific heat * change in temperature q = (1300 g)(4.180 J/gC)(100 C - 20 C) = 4.3 X 105 Joules of heat energy ========================
That depends on the amount of water, on how cold it was initially, and on how fast heat energy is supplied.
4.1858 joules of energy will raise the temperature of 1 g of water by 1oC. Thus, 4.1858 * 955 * 80 = 319795.12 joules of energy is required to raise the temperature of 955 g of water by 1oC.
Heat required to have such a change of state is called latent heat. If L J/kg is the latent heat per kg of water then for M kg of water we need M* L joule of heat energy
The specific heat of water is 4,186 J/g.K.
A calorie of energy (NOT to be confused with a Calorie, they are different so watch the caps) is the amount necessary to heat 1 gram of water 1oC, so 30 calories are needed to heat 30 g of water 1 degree. To heat it 70oC would take 2100 calories (or 2.1 Calories) of energy.
No heat (energy) is required to freeze water (from liquid to solid). Freezing RELEASES energy (heat), as it is an exothermic event. If you want to know how much energy is release, you need to know the heat of fusion for water, and then multiply that by the mass of water being frozen.
Due to more volume mass, it will take longer, but the 2 liters with double mass will eventually heat up the same 10 FIVE degrees with the same energy amount.
The specific heat of water determines how much energy is needed to heat water.