This question cannot be answered as currently posed for three reasons:
The initial temperature is not specified
The material being heat up is not specified
kWatts is a unit of power, not energy.
It is also not clear how much of the mystery substance is involved or what phase it is in. It seems likely that the intention was to ask about heating 4000 liters of something, but the abbreviation for liters is not "lt".
Temperature is the measure of how much heat energy something has. Just like distance is the measure of how far apart two points are. 0 degrees centigrade for example is the point at which water freezes whereas 100 degrees is the boiling point of water. So a warm bath tub may have a lower temperature than a candle flame, but it has more heat energy stored in it overall because it would take a lot of candles to heat up a bath tub.
2500
A watt is a measure of energy, which may or may not be heat, but heat is considered to be the simplest form of energy and is an easy way to compare amounts of energy. Another measure of energy that is easy to work with is a calorie, which is the amount of energy needed to raise the temperature of 1 gram of water by 1 degree C. In these terms without special conditions, this applies only between 0 and 100 degrees C, because freezing and boiling make the equations much more complicated. A watt is approximately 86 calories, meaning that applied to a gram of water would raise its temperature by 86 degrees centigrade. A kilowatt is 1000 watts meaning that it could raise the temperature of that gram of water by 86000 degrees--at least theoretically, but that image is all but useless. So let's say that a kilowatt represents enough heat to raise the temperature of a liter (1000 g) of water by 86 degrees C.
Ok, lets assume that a pool of water and the air are at the same temperature. There are a number of ways you can lose heat to the surroundings, however in this example the most important reason is: Conduction. This is due to direct contact with surrounding particles. As the Particles in you body vibrate with energy they collide with surrounding air or water particles. You will thus lose much more energy to water than to air as water is much better at conducting heat away from you. (There are many times more water particles to transfer the energy away). In terms of heat capacity, if water has a higher heat capacity then it will take more energy from your body to heat it up. Seeing as you body is warmer than the surrounding water, the water will take more of your thermal energy to reach thermal equilibrium with you.
Heat is defined as the total kinetic energy of all the atoms and molecules that make up a substance.Temperature is a measure of the average kinetic energy of the individual atoms or molecules in a substance.
To calculate the energy needed to change ice at -32.9 degrees to water at 75 degrees, you need to consider the energy required for three steps: Heating ice from -32.9 degrees to 0 degrees (specific heat capacity of ice) Melting ice at 0 degrees into water at 0 degrees (latent heat of fusion of ice) Heating water from 0 degrees to 75 degrees (specific heat capacity of water) Once you have the energy needed for each step, you can add them together to find the total energy required.
It has a much higher volume of water compared to the tea cup. It takes less energy to heat a small amount of liquid such as a tea cup.
To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.
Specific heat capacity tells you how much stuff energy can store. specific heat capacity is the amount of energy needed to raise the temperature of 1kg of a substance by 1 degrees celsius. water has a specific heat capacity of 4200 J/kg degrees celsius.
Water at 0 degrees Fahrenheit still has heat energy and molecular activity, but it is in a solid state as ice. The molecules are still vibrating, just at a much slower rate compared to when water is in a liquid state.
The process involves increasing the temperature of water from 8°C to 100°C and then changing its phase to steam at 100°C. The total heat energy required can be calculated using the specific heat capacity of water and the heat of vaporization. The formula Q = mcΔT can be used to find the heat energy needed, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.
The specific heat capacity of water is 4.18 J/g°C. The energy needed to heat 3.0 g of water can be calculated using the formula: energy = mass x specific heat capacity x temperature change. Plugging in the values gives: energy = 3.0 g x 4.18 J/g°C x (28°C - 22°C) = 75.24 Joules.
The specific heat capacity of water is 4.186 J/g°C. Since there are 1000 grams in a kilogram, it would require 20,930 Joules of energy to increase the temperature of a kilogram of water by 5 degrees Celsius.
The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate the heat energy as follows: Q = 15g * 4.18 J/g°C * 25°C = 1567.5 J. Therefore, 1567.5 Joules of heat energy will be required to raise the temperature of 15 grams of water by 25 degrees Celsius.
Heat required to have such a change of state is called latent heat. If L J/kg is the latent heat per kg of water then for M kg of water we need M* L joule of heat energy
A calorie of energy (NOT to be confused with a Calorie, they are different so watch the caps) is the amount necessary to heat 1 gram of water 1oC, so 30 calories are needed to heat 30 g of water 1 degree. To heat it 70oC would take 2100 calories (or 2.1 Calories) of energy.
No heat (energy) is required to freeze water (from liquid to solid). Freezing RELEASES energy (heat), as it is an exothermic event. If you want to know how much energy is release, you need to know the heat of fusion for water, and then multiply that by the mass of water being frozen.