The process involves increasing the temperature of water from 8°C to 100°C and then changing its phase to steam at 100°C. The total heat energy required can be calculated using the specific heat capacity of water and the heat of vaporization. The formula Q = mcΔT can be used to find the heat energy needed, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
The specific heat capacity of water is 4.18 J/g°C. The energy needed to heat 3.0 g of water can be calculated using the formula: energy = mass x specific heat capacity x temperature change. Plugging in the values gives: energy = 3.0 g x 4.18 J/g°C x (28°C - 22°C) = 75.24 Joules.
The amount of energy needed to raise the temperature of 1 kg of a substance by 1 degree Celsius is called the specific heat capacity of the substance. Specific heat capacity is usually measured in joules per kilogram per degree Celsius (J/kg°C). Different substances have different specific heat capacities.
raise the temperature of the body by 1 Celsius
The specific heat capacity of water is 4.186 J/g°C. Since there are 1000 grams in a kilogram, it would require 20,930 Joules of energy to increase the temperature of a kilogram of water by 5 degrees Celsius.
To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.
To convert 4 kg of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to calculate the heat required to raise the temperature of ice to 0 degrees Celsius, melt the ice to water at 0 degrees Celsius, raise the temperature of water to 100 degrees Celsius, and then convert water to steam at 100 degrees Celsius. The total amount of heat needed can be calculated using the specific heat capacities and latent heats of fusion and vaporization of water.
Because degrees Celsius means the same as degrees centigrade, the answer is 18 degrees. Better use the correct word "degrees Celsius."
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
To answer this, it is needed to convert one of the temperatures to the same scale as the other. To convert oC to oF, the formula is: F = 9 x C / 5 + 32 So 12oC in Fahrenheit is: F = 9 x 12 / 5 + 32 = 53.6 12oF is less than 53.6oF = 12oC. So 12oF is colder than 12oC.
Specific heat capacity tells you how much stuff energy can store. specific heat capacity is the amount of energy needed to raise the temperature of 1kg of a substance by 1 degrees celsius. water has a specific heat capacity of 4200 J/kg degrees celsius.
If its in Celsius then another 13 degrees are needed because water boils at 100 degrees Celsius
8.200 J
539 calories per gram for heat of vaporization plus 1 cal/gram/degree C 100 degrees C - 80 degrees C = 20 degrees C (539 calories + 20 calories) X 50 kg X 1000 gm/kg = 27950000 cal = 27,950 kcal
True. A calorie is defined as the amount of heat energy needed to raise the temperature of 1 gram of water by 1 degree Celsius.
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
because I like cheese