You haven't given units for 9.90. nm, wavenumbers? metres, centimetres? E=hc/lambda, speed of light in metres, wavelength in metres
There is no such thing as "long energy" or "short energy". The electromagnetic spectrum is:Radio waves; microwaves; infrared; visible light; ultraviolet; x-rays; gamma rays. In this list, going from left to right: * The energy per photon increases. * The frequency increases. * The wavelength decreases. Thus, for instance, gamma rays have the LARGEST energy per photon; the LARGEST frequency; and the SHORTEST wavelength.
The energy per photon of infrared radiation can be calculated using the formula E = hc/λ, where h is the Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength in meters. Converting the wavelength to meters (25 micrometers = 25 x 10^-6 meters), we can plug the values into the formula to calculate the energy per photon. This results in E ≈ 7.95 x 10^-20 Joules per photon.
infrared
The energy of this photon is 3,7351.10e-19 joules.
The units are missing from your wavelength. Perhaps it is 5.20 micrometers. Red light is about 635 nm (0.635 micrometer). Infrared would have to be a longer wavelength than that. Energy = h*c/(wavelength), where h is Planck's constant (approx 6.63 x 10^-34 Joule second). So we have (6.63 x 10^-34 Joule sec)(3 x 10^8 m/s) / (5.2 x 10^-6 m) = 3.83 x 10^-20 Joules. Or 0.239 electron Volts.
Visible light has a higher frequency, a higher energy per photon, and a smaller wavelength, compared to infrared.
Wavelength, frequency, and energy carried by each photon (light quantum).
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
As the wavelength of a photon increases, its frequency decreases. This means the energy of the photon decreases as well, since photon energy is inversely proportional to its wavelength.
The energy of a photon with a wavelength of 827nm can be calculated using the equation E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. The type of radiation corresponds to near-infrared, which lies just beyond the visible spectrum.
To find the wavelength of the photon, you can use the formula: wavelength = (Planck's constant) / (photon energy). Substituting the values, the wavelength is approximately 1.024 x 10^-7 meters.
Yes, a photon with a wavelength of 420nm contains more energy than a photon with a wavelength of 790nm. This is because energy is inversely proportional to wavelength, meaning shorter wavelengths have higher energy.
Photon Energy E=hf = hc/w thus wavelength w= hc/E or the wavelength is hc divided by the energy of the photon or w= .2 e-24 Joule meter/Photon Energy.
The total energy of a photon with a wavelength of 3000 A is divided into two photons, one red photon with a wavelength of 7600 A, and another photon with a shorter wavelength. To calculate the wavelength of the second photon, you can use the conservation of energy principle, where the sum of the energies of the two new photons is equal to the energy of the original photon. This will give you the wavelength of the other photon.
The wavelength of a photon can be calculated using the equation: wavelength = Planck's constant / photon energy. Given the photon energy, you can plug in the values to find the corresponding wavelength.
The wavelength is 436 nm.
IR: longer wavelength, lower frequency, lower energy per photon.Visible: medium wavelength, medium frequency, medium energy per photon.UV: shorter wavelength, higher frequency, higher energy per photon.