Twice the energy means twice the frequency, and therefore half the wavelength.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
Energy = hc/w= .2E-24/400E-9 = .5E-18 joules x 6.25E18 ev/J=3.125 ev.
The energy of light whose wavelength is 4,06 x e-11m is 4,8927.e-15 joule.
what is the energy of a photon that has a frequency of 5.0x1014 Hz?
I presume you asking, "How can an atom of size about 1 angstrom absorb a photon whose wavelength is 5000 angstroms? Wouldn't the photon be too large for that atom?" The paradox is resolved in this way: the instant you start to discuss electro-magnetic radiation as a photon instead of a transverse electro-magnetic wave, then you negate the wave-length aspect of the light. Instead, you view light as a collection of photons -- particles whose "size" (if that word has meaning) is point-like -- with a specific energy instead of specific wavelength. A photon is NOT a snake-like wave, vibrating like a rubber band, with a length at least that of its wave-length, as it moves through a medium. A photon is a point particle with a specific energy. You can describe light as a EM wave with a wave-length OR as a collection of point particles. You can NOT do both at the same time. Light exhibits the characteristics of one OR the other, but NEVER both.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
Energy = hc/w= .2E-24/400E-9 = .5E-18 joules x 6.25E18 ev/J=3.125 ev.
First get the wavelength in meters by multiplying Plancks constant (in units of J-sec) times the speed of light (in m/sec) and divided by the energy. Then change to nanometers by multiplying by 1 billion.
The energy of light whose wavelength is 4,06 x e-11m is 4,8927.e-15 joule.
38.4 *10-34J
what is the energy of a photon that has a frequency of 5.0x1014 Hz?
I presume you asking, "How can an atom of size about 1 angstrom absorb a photon whose wavelength is 5000 angstroms? Wouldn't the photon be too large for that atom?" The paradox is resolved in this way: the instant you start to discuss electro-magnetic radiation as a photon instead of a transverse electro-magnetic wave, then you negate the wave-length aspect of the light. Instead, you view light as a collection of photons -- particles whose "size" (if that word has meaning) is point-like -- with a specific energy instead of specific wavelength. A photon is NOT a snake-like wave, vibrating like a rubber band, with a length at least that of its wave-length, as it moves through a medium. A photon is a point particle with a specific energy. You can describe light as a EM wave with a wave-length OR as a collection of point particles. You can NOT do both at the same time. Light exhibits the characteristics of one OR the other, but NEVER both.
Divide the speed of light (in meters/second) by the wavelength (in meters). The answer is in Hz (1/second). Divide that answer by a million to get MHz.
The wavelength is w=hc/E= 1.25E-6evm/120 = 10.4 nanometer.
An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.
12.5 terahertz. If your wavelength is in meters.
The answer is in the question! 5 Hz Also, a wavelength cannot be 5 cycles - wrong units.