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The energy of a photon is related to its?
The energy of a photon is related to its frequency or wavelength through the equation E=hf, where E is energy, h is Planck's constant, and f is frequency. Alternatively, you can use the equation E=hc/λ, where λ is the wavelength and c is the speed of light.
How can I calculate the energy of a photon if I know the wavelength?
You can use the equation E = hc / λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the photon in meters. Plug in the values to calculate the energy in joules.
Describe the relationship between the wavelength and it's energy?
c is the speed of sound or the speed of light. You must know what you need. There is a relationship between the wavelength lambda and the frequency f. But forget the energy! c= lambda times f f is proportional to 1 / lambda. f = c / lambda lambda = c / f
A photon has a wavelength of 6.2 meters. Calculate the energy of the photon in joules. (Planck's constant is 6.626 and times 10-34 joule seconds the speed of light is?
To calculate the energy of a photon, we use the equation E = hc/λ, where E is energy, h is Planck's constant, c is the speed of light, and λ is wavelength. Plugging in the values, E = (6.626 x 10^-34 J s * 3 x 10^8 m/s) / 6.2 m ≈ 3.2 x 10^-26 Joules.
What is the energy of photon?
the energy of a photon is h times f
How does the energy of three photons of blue light compare with that of one photon of blue light from the same source?
If the color (frequency, wavelength) of each is the same, then each photon carries the same amount of energy. Three of them carry three times the energy that one of them carries.
The energy of a photon is related to its?
The energy of a photon is related to its frequency or wavelength through the equation E=hf, where E is energy, h is Planck's constant, and f is frequency. Alternatively, you can use the equation E=hc/λ, where λ is the wavelength and c is the speed of light.
What is the frequency in hertz and the energy in joules of an x-ray photon with a wavelength of 2.32 Å?
For the frequency, first convert the wavelength to meters (divide the number of Angstroms by 1010), then use the formula: wavelength x frequency = speed. Using the speed of light in this case. Solving for frequency: frequency = speed / wavelength. To get the photon's energy, multiply the frequency times Planck's constant, which is 6.63 x 10-34 (joules times seconds).
That An electron requires 4 times 10-17 j of energy to be removed from it's atom what is the wavelength of a photon that has this much energy?
The wavelength is w = hc/E = .2E-24/4E-17 = 5E-9 meters.
How can I calculate the energy of a photon if I know the wavelength?
You can use the equation E = hc / λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the photon in meters. Plug in the values to calculate the energy in joules.
When a calcium salt is heated in a flame a photon of light with an energy of 3.2 and times 10 and 820919 J is emitted. On the basis of this fact and the table below what color would be expected for th?
When a calcium salt is heated in a flame and emits a photon with an energy of 3.2 x 10^-19 J, we can determine the color of the light based on the energy of the photon. The energy of the photon corresponds to a wavelength of approximately 620 nm, which falls within the visible spectrum. This wavelength is associated with the color orange-red. Therefore, we would expect the flame to display an orange-red color.
Describe the relationship between the wavelength and it's energy?
c is the speed of sound or the speed of light. You must know what you need. There is a relationship between the wavelength lambda and the frequency f. But forget the energy! c= lambda times f f is proportional to 1 / lambda. f = c / lambda lambda = c / f
How are engery and frquency of electromagnetic radiation related?
(The energy of each photon) is (the photon's frequency) times (Planck's Konstant). (The total energy in a beam of it) is (the energy of each photon) times (the number of photons in the beam).
If the inner accretion disk around a black hole has a temperature of 1000000 K at what wavelength will it radiate the most energy?
For a thermal radiation source, the peak of the blackbody radiation curve is at a photon energy 2.8 times the temperature in electron-volts. The temperature in electron-volts is 1/11,600 times the temperature in Kelvin. Use E = hv to convert from the photon energy (E) to photon frequency, using Plank's constant h. Use v = c/(lambda) to convert from the photon frequency to the wavelength. The result: these hot plasmas radiate X-rays, and the peak wavelength is about 50 Angstroms, i.e. 5 nm.
How do you find energy when given frequency?
The energy of a photon of electromagnetic radiation is(Photon's frequency) times (Planck's Konstant) .
A photon has a wavelength of 6.2 meters. Calculate the energy of the photon in joules. (Planck's constant is 6.626 and times 10-34 joule seconds the speed of light is?
To calculate the energy of a photon, we use the equation E = hc/λ, where E is energy, h is Planck's constant, c is the speed of light, and λ is wavelength. Plugging in the values, E = (6.626 x 10^-34 J s * 3 x 10^8 m/s) / 6.2 m ≈ 3.2 x 10^-26 Joules.
What is the wavelength in nm of a photon whose energy is 4.7 x 10-14 J?
First get the wavelength in meters by multiplying Plancks constant (in units of J-sec) times the speed of light (in m/sec) and divided by the energy. Then change to nanometers by multiplying by 1 billion.
