First get the wavelength in meters by multiplying Plancks constant (in units of J-sec) times the speed of light (in m/sec) and divided by the energy. Then change to nanometers by multiplying by 1 billion.
0,0042265 nm
The standard equation here is E=nhf. E is energy, n is number of photons, h is Planck's Constant, and f is frequency. For a single photon you can get rid of the 'n', so it looks like E=hf. For this problem, you first have to convert the wavelength to frequency. This is done by dividing the speed of the wave per second (i.e., the speed of light), by the wavelength. This is (3*108 m/sec)/(4.60*10-7 m) which simplifies to 6.52*1014/sec. Now all you have to do is multiply the frequency by Planck's constant, which is 6.626068 × 10-34 m2 kg/s. So, (6.626068 × 10-34 m2 kg/s) * (6.52*1014/sec) = 4.3202*10-19 kg m2/s2 or 4.3202*10-19 Joules. If you want proper significant figures, then the answer is 4.3*10-19 Joules. Note: 4.3x10-19 joules equals 2.7 eV (electron volts)
The energy is 2,9619.e-19 J.
2.8x10-19 JE = hν, and ν = c/λ. λ is wavelength, c is the speed of light (3.0 x 108 meters/second), E is energy, and h is 6.626 x 10-34. 3.0 x 108/715 = 419580.42. 419580.42 x 6.626 x 10-34 = 2.78 x 10-28 joules.
1018 meters = one quintillion meters = 1 billion billion meters = about 110 light yearsAbout 6.2 * 1014 miles
250,000,000 in Scientific Notation is: 2.5*10^8
A photon with energy 3.0 x 10-19 J A photon with wavelength 525 nm A photon with frequency 7.6 x 1014 Hz A photon with frequency 2 x 1015 Hz
384 nm (apex)
The frequency of the photon is 4.92 1014 Hz.
Wavelength = 3 x 108 / 6.9 *1014 lambda = 4.35*10-7 m Almost the colour seems to be violet.
4.25 10-19 j
3.905x10^-19 J
2.96 x 10^-19 J
4.78 x 10-19
The longest wavelengths of light are the lowest frequencies (and the lowest energy and the longest period, too). These are the reds, and moving up the spectrum, we encounter orange, yellow, green, blue and violet. The violet light has the shortest wavelength (highest frequency), and the highest energy. The infrared (IR) is below the red (longer wavelength and lower frequency), and the ultraviolet (UV) is above the violet (shorter wavelength and higher frequency).
- frequency of this light : c=ln, so n=c/l (and remembering that 1 nm = 1 x10-9 m) = (3.00 x 108 m/s)/554x 10-9 m) = 5.42 x 1014 1/s - the energy of a photon of this light: E(photon) = hn = (6.6262 x 10-34 J·s)(5.42 x 1014 1/s) = 3.59 x 10-19 J
The wavelength is (speed of the wave) / 2.06 x 1014 .If the wave is an electromagnetic one propagating through vacuum,then the wavelength is3 x 108 / 2.06 x 1014 = 0.001456 millimeter = 1,456 nanometer (rounded)
The wavelength is 671 nm.