2.8x10-19 J
E = hν, and ν = c/λ. λ is wavelength, c is the speed of light (3.0 x 108 meters/second), E is energy, and h is 6.626 x 10-34. 3.0 x 108/715 = 419580.42. 419580.42 x 6.626 x 10-34 = 2.78 x 10-28 joules.
First get the wavelength in meters by multiplying Plancks constant (in units of J-sec) times the speed of light (in m/sec) and divided by the energy. Then change to nanometers by multiplying by 1 billion.
Each photon has an energy of 4.9*10^-19 J.
Short wave radiation. You might separate it to X-ray or Ultra-Violet but basically, any wavelength shorter than 400 nm had degree of harm. The shorter wavelength the more energy/photon and higher risk of causing DNA damage and resulting to cancer.
If a wavelength of light emitted from a particular red diode laser is 651 nm, its wavelength would be equivalent to 0.000000651 meters.
Visible 'light' ranges from roughly 380 to 750 nanometers (billionths of a meter). It can vary somewhat for different individuals' eyes. If electromagnetic radiation has a wavelength longer than about 750nm or shorter than about 380nm, you may still call it 'light' if you want, but the human eye doesn't respond to it.
3.84 x 10-19 joules.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, the energy of a photon with a wavelength of 518 nm is approximately 3.82 eV.
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
The energy of a photon with a wavelength of 500 nm is approximately 2.48 keV.
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
Transition B produces light with half the wavelength of Transition A, so the wavelength is 200 nm. This is due to the inverse relationship between energy and wavelength in the electromagnetic spectrum.
610 nm
The energy of this photon is 3,7351.10e-19 joules.
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.
To determine the energy of a photon of orange light with a wavelength of 600 nm, we can use the formula E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Converting the wavelength to meters (600 nm = 600 x 10^-9 m), we can plug the values into the formula to find the energy of the photon. The energy of a photon of orange light with a wavelength of 600 nm is approximately 3.31 x 10^-19 joules.
4.9695 nm