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The standard equation here is E=nhf. E is energy, n is number of photons, h is Planck's Constant, and f is frequency. For a single photon you can get rid of the 'n', so it looks like E=hf. For this problem, you first have to convert the wavelength to frequency. This is done by dividing the speed of the wave per second (i.e., the speed of light), by the wavelength. This is (3*108 m/sec)/(4.60*10-7 m) which simplifies to 6.52*1014/sec. Now all you have to do is multiply the frequency by Planck's constant, which is 6.626068 × 10-34 m2 kg/s. So, (6.626068 × 10-34 m2 kg/s) * (6.52*1014/sec) = 4.3202*10-19 kg m2/s2 or 4.3202*10-19 Joules. If you want proper significant figures, then the answer is 4.3*10-19 Joules.

Note: 4.3x10-19 joules equals 2.7 eV (electron volts)

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Related Questions

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