The energy of a photon is inversely propotional to its wavelength. The wavelength of a blue photon is less than that of a red photon. That makes the blue photon more energetic. Or how about this? The energy of a photon is directly proportional to its frequency. The frequency of a blue photon is greater than that of a red photon. That makes the blue photon more energetic. The wavelength of a photon is inversely proportional to its frequency. The the longer the wavelength, the lower the frequency. The shorter the wavelength, the higher the frequency.
A photon of blue light has a higher frequency and similarly a higher energy than a photon of orange light which has a greater wavelength.
A photon of green light carries more energy than a photon
of orange light does, because it has a higher frequency.
A blue photon has a higher energy, therefore more equivalent mass, therefore more momentum.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
Red does as it absorbs photons at blue end of the spectrum( the higher energy) and reflects light at the red end of the spectrum (a lower energy). While the blue light absorbs energy at the red end of the spectrum and reflects blue light
A rough definition of intensity (how intense) a light is might be how bright (the brightness) the light is. Intensity speaks to the luminance or luminosity of the light source. Under that definition, either red or blue light could be more intense. But if the information regarding the energy of light according to its color (or its wavelength or frequency), we would find that a photon of blue light has more energy than a photon of red light. Blue light has a shorter wavelength or higher frequency, and electromagnetic energy with higher frequency or shorter wavelength has more energy than light of the same intensity but of lower frequency or longer wavelength.
Red light has less energy per photon than blue light, so to get the same energy we would need more red photons.
The violet light has more energy than the red light. Red light is lower on the electromagnetic spectrum, meaning it has a lower frequency (or longer wavelength). You'll recall the colors of the rainbow as red, orange, yellow, etc., and these are the colors going up the frequency spectrum. Photons higher on the spectrum are higher in frequency and energy.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
Whatever the colors are, the brighter light results from the beam of more photons. But each individual blue photon carries more energy than each individual red photon.
It really just depends on you, I would have to say red because blue is more of a calm color. When red is more of a exciting, bright color.
Yes it does.
Red... Red is the most energetic color in ROY G BIV violet being the least energetic.
Red does as it absorbs photons at blue end of the spectrum( the higher energy) and reflects light at the red end of the spectrum (a lower energy). While the blue light absorbs energy at the red end of the spectrum and reflects blue light
A rough definition of intensity (how intense) a light is might be how bright (the brightness) the light is. Intensity speaks to the luminance or luminosity of the light source. Under that definition, either red or blue light could be more intense. But if the information regarding the energy of light according to its color (or its wavelength or frequency), we would find that a photon of blue light has more energy than a photon of red light. Blue light has a shorter wavelength or higher frequency, and electromagnetic energy with higher frequency or shorter wavelength has more energy than light of the same intensity but of lower frequency or longer wavelength.
Wavelength Frequency and Photon Energy
Red light has lower energy photons than blue light. Ultra-violet is even more energetic.
Red light has less energy per photon than blue light, so to get the same energy we would need more red photons.
It is not meaningful to talk about "amplitude of the visible light spectrum". One might think that more intense light would mean greater amplitude of the light wave, but it just means more photons. "Visible light" is made up of photons. A single photon has a certain quantifiable energy, and that energy is discussed in terms of frequency or wavelength. A photon with low frequency (towards the red end of the visible light spectrum, for instance) is less energetic than a photon with high frequency (towards the blue end and beyond). For all intents and purposes, the amplitude of a photon wave-packet could be said to be of "unit amplitude", the amplitude of light.
I think it is because a photon has less energy that is why it has less ability than a gamma ray photon