The energy increases as the frequency increases.
The frequency decreases as the wavelength increases.
So, the energy decreases as the wavelength increases.
V=f *lambda where v = wave speed, f=frequency and lambda= wavelength. Frequency increase as the energy of a wave increases because E=hf where h is a constant so E/h=f. if E increase f has to increase. Wavelength decreases because if the frequency increases the wavelength would also have to decrease as v/f=lambda. Therefore the larger the frequency is the smaller the wave lengthen will be.
inversely
The Planck-Einstein relation was significant in the development of quantum theory because it established the relationship between the energy of a photon and its frequency, providing a key insight into the quantization of energy in the quantum world. This relation helped to lay the foundation for the understanding of the behavior of particles at the atomic and subatomic levels, leading to the development of quantum mechanics.
A very very tiny amount of matter is removed and a very large amount of energy is produced.
It is directly related the distance from centre of the earth.As P.E=mgh, or if you are a college student, U=-GMm/r, now if r increases , U becomes less negative, that is , it actually increases.
As the wavelength of a photon increases, its frequency decreases. This means the energy of the photon decreases as well, since photon energy is inversely proportional to its wavelength.
The energy of a photon is inversely proportional to its wavelength. This means that as the wavelength increases, the energy of the photon decreases. Conversely, as the wavelength decreases, the energy of the photon increases.
As frequency increases, the wavelength decreases and the energy of each photon (in the case of light) increases. Similarly, the period (time taken for one cycle) decreases as frequency increases.
Remember that for any wave, wavelength x frequency = speed (of the wave). So, as the wavelength increases, the frequency decreases. Also, since the energy of a photon is proportional to the frequency, the energy will decrease as well in this case.
-- energy per photon increases -- wavelength decreases
As the wavelength of an electromagnetic wave decreases, the frequency of the wave increases. This means that the energy carried by the wave also increases, as energy is directly proportional to frequency. Therefore, shorter wavelength corresponds to higher frequency and energy in an electromagnetic wave.
The energy of a photon depends on it's frequency
Color wavelength and photon energy are inversely related. This means that as the wavelength of light decreases and the frequency increases, the energy of the photons also increases. Shorter wavelengths correspond to higher energy photons, such as in the case of ultraviolet light having higher energy than visible light.
The energy of a photon is inversely propotional to its wavelength. The wavelength of a blue photon is less than that of a red photon. That makes the blue photon more energetic. Or how about this? The energy of a photon is directly proportional to its frequency. The frequency of a blue photon is greater than that of a red photon. That makes the blue photon more energetic. The wavelength of a photon is inversely proportional to its frequency. The the longer the wavelength, the lower the frequency. The shorter the wavelength, the higher the frequency.
The relationship between photon frequency and energy is direct and proportional. As the frequency of a photon increases, its energy also increases. This relationship is described by the equation E hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon.
Photon energy is directly proportional to frequency. This relationship is described by the equation E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon. This means that as frequency increases, photon energy also increases.
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.