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What else can I help you with?
How do you find the energy of a photon?
You need to know the photon's frequency or wavelength. If you know the wavelength, divide the speed of light by the photon's wavelength to find the frequency. Once you have the photon's frequency, multiply that by Planck's Konstant. The product is the photon's energy.
What is the energy of a photon?
the energy of a photon is h times f
Describe the relationship between the wavelength and it's energy?
c is the speed of sound or the speed of light. You must know what you need. There is a relationship between the wavelength lambda and the frequency f. But forget the energy! c= lambda times f f is proportional to 1 / lambda. f = c / lambda lambda = c / f
Determine the energy of 1.80 mol of photons for each what kinds of light?
To determine the energy of 1.80 mol of photons, you would need to know the frequency or wavelength of the light. Each individual photon's energy is determined by E=hf or E=hc/λ, where h is Planck's constant, f is the frequency, c is the speed of light, and λ is the wavelength. Without this information, you cannot calculate the energy of the photons for different kinds of light.
How do you find wavelength if you've been given the energy?
You can use the equation E = hc/λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength. Rearrange the equation to solve for λ by dividing both sides by E and then multiplying by hc.
How do you find the energy of a photon?
You need to know the photon's frequency or wavelength. If you know the wavelength, divide the speed of light by the photon's wavelength to find the frequency. Once you have the photon's frequency, multiply that by Planck's Konstant. The product is the photon's energy.
What is the energy of a photon?
the energy of a photon is h times f
What are the frequency and wavelength of a photon which jumped from energy level 5 to energy level 2?
Use this formula to find frequency. Frequency (Hertz) = (3.29 X 10^15 Hz)*Z^2*(1/nf^2 - 1/ni^2) use this to find wavelength Wavelength = speed of light/frequency in Hz Now, you need to know what the Z number (atomic number-Carbon = 6, for instance ) is of the element that generated the photon of light.
How do you calculate energy per mole of photons if you know joules per photon?
To calculate the energy per mole of photons from the energy per photon, you need to multiply the energy per photon by Avogadro's number (6.022 x 10^23) to account for the number of photons in a mole. The formula is: Energy per mole of photons = Energy per photon x Avogadro's number.
How many photons will be required to raise the temperature of 2.4g of water by 2.5K?
To determine the number of photons required to raise the temperature of 2.4g of water by 2.5K, you would need to know the energy of each photon, which depends on the wavelength/frequency of the light source. With this information, you can calculate the total energy needed to raise the temperature of the water by 2.5K and then convert this energy into the number of photons using the energy per photon value.
A typical wavelength of infrared radiation emitted by your body is 25 micrometers. What is the energy per photon of such radiation?
* E = hf = hc/wavelength = (6.63 x 10-34 J*s)(3.00 x 108 m/s)/(25 x 10-6 m) = 7.9 x 10-21 J per photon. This is the energy of a photon at that wavelength. == The person who asked the question answered it. Why ask a question to which you already know the answer? And the body under "normal" conditions radiates infrared (IR) most strongly at about 10 micrometers.
Describe the relationship between the wavelength and it's energy?
c is the speed of sound or the speed of light. You must know what you need. There is a relationship between the wavelength lambda and the frequency f. But forget the energy! c= lambda times f f is proportional to 1 / lambda. f = c / lambda lambda = c / f
A photon has a wavelength 624 nm. Calculate the energy of the photon in joules.?
You know that,E = h*c/λWhereh = Plank's constant = 6,626 x 10-34 J*sc = speed of light = 3*108 m/sλ = greek letter lambda representing the wavelength =624nm => 6,24 *10-7mand therefore [(6.626 X 10^-34 J) X (3 X 10^8 m/s)] / (6.24 x 10^-7) = 3.18 x 10^-19 ... That should be right!
Determine the energy of 1.80 mol of photons for each what kinds of light?
To determine the energy of 1.80 mol of photons, you would need to know the frequency or wavelength of the light. Each individual photon's energy is determined by E=hf or E=hc/λ, where h is Planck's constant, f is the frequency, c is the speed of light, and λ is the wavelength. Without this information, you cannot calculate the energy of the photons for different kinds of light.
How do you find wavelength if you've been given the energy?
You can use the equation E = hc/λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength. Rearrange the equation to solve for λ by dividing both sides by E and then multiplying by hc.
How do you calculate the wavelenght of a photon?
You need to know speed and frequency. The speed of all photons is the speed of light, 3.0 x 108m/s. The equation for finding wavelength when frequency and speed are known is λ = ƒ/c , where c is the speed of light, f is the frequency in Hz, and λ (Greek letter lambda) is the wavelength in meters.
How can gravity affect a photon's path when a photon is massless?
The photon is only massless when it's at rest. But it's never at rest ... it's always moving at the speed of light, and at that speed, it has mass. How much mass ? Easy to calculate! (Maybe meaningless, but easy to calculate.) We can easily find the energy of the photon, because it's simply (frequency of the radiation) times (Planck's Konstant). The photon's energy is all kinetic energy, which we know is [ 1/2 M V2 ], and 'V' is always ' c '. So there you are! If you know the frequency (or wavelength) of the radiation, then the mass of the photon practically falls right out, onto the floor. It's [ 2 h (freq)/c2 ] . By the way, speaking of weird stuff, I skipped over the part along the way where the photon's energy is all kinetic energy . . . [ E = 1/2 M V2 ] but the photon's 'V' is always ' c ', so [ E = 1/2 M c2 ] . Does this remind us of any other little equation we've seen before ? Except for that factor of 1/2 , they're both the same equation. What is the connection, and what is going on ? I have no idea.
