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The needed energy is 10 calories.
42 J
mmmm enthalpy
the amount of heat needed to raise the temeperature of 1kg of some material by 1 degrees celsius(or 1K)
Mass, heat capacity, the desired raise in temperature.
The needed energy is 10 calories.
quite abit
48
Any amount of energy you like greater than 0; the larger the amount of energy you give it, the larger the temperature increase will be. Perhaps you should specify by how much temperature you want the gallon of water to increase and you may get a more specific answer.
42 J
mmmm enthalpy
The definition of a calorie is that, it's the energy needed to increase the temperature of 1 kilogram of water by 1 °C.
1 calorie increases 1 gram of water by 1 degree celsius. 4.18 Joules are needed to increase the temperature of 1 gram of water by 1 degree celsius. To reduce the 1 gram of water 1 degree celsius it would have to give off 1 calorie of energy. To calculate the energy multiply the mass in grams of water by 4.18 and by the change in temperature. The energy = 4.18 x m x change in T. The answer is in Joules. If you are using calorie as the unit of energy, replace 4.18 J by 1 C. Note that food is measured in kilocalories (Calories) not metric calories.
Specific heat capacity is the amount of energy or heat required to raise the temperature of a unit mass of a substance by one kelvin. So if the specific heat capacity is high then you would require more energy or heat to raise its temperature. The specific heat capacity does not really have anything to do with how much you can increase an objects temperature. IT HAS TO DO WITH THE ENERGY NEEDED TO INCREASE THE TEMPERATURE.
The large calorie, kilogram calorie, dietary calorie or food calorie approximates the energy needed to increase the temperature of 1 kilogram of water by 1 °C.
ewan
As soon as the temperature drops below the dew point, water will condense from water vapor.