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q = (42.5 g)(0.902 J/gC)(25o C - 4750o C)

= - 1.8 X 105 Joules

====================negative can be ignored for absolute value, but remember the direction the heat is going.

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Q: How much energy is released when 42.5g of aluminum vapor are cooled from 4750 degrees Celsius to 25 degrees Celsius?
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