Q = 3 000 . 0,444 . ΔT (joules)
ΔT is the difference of temperature.
1935 J
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material
(Explanation): remember to convert the 2kg to grams, then multiply in this equation Q=(2000)(0.45)(3) to get Q=2700J
Iron naturally exists in solid state and heat is required for its liquifaction so liquid iron has high thermal energy.
Temperature is the degree of hotness. So, if you have say 1kg or iron and you put 100 calories of heat into it, and do them same to a 2kg lump of iron, the first one will become hotter than the second, although they will both contain the same amount of heat. This heat is part of the internal energy of the iron lumps.
538J
1935 J
The formula is: 0,108 x 3000 x (T1 -T2), in kilocalories.
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material
38 cal
(Explanation): remember to convert the 2kg to grams, then multiply in this equation Q=(2000)(0.45)(3) to get Q=2700J
yes
It means that it takes more energy to produce the same increase in temperature in the same amount. For example it takes more energy to raise the temperature of 1 gram of water by 1 degree than it does to do the same with 1 gram of iron. Therefore water has a higher specific heat.
A substance's molar specific heat capacity is the amount of energy required to raise one mole of that substance 1 degree Celsius.For water, this is exactly one calorie, assuming the state of the water does not change. Otherwise, it depends on the substance, and the substance's current temperature and state.for apex its latent
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
Iron naturally exists in solid state and heat is required for its liquifaction so liquid iron has high thermal energy.
0.11cal/g degrees C