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1935
3.50 J
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam
1935 J (apex)
15480.80
1935
3.50 J
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam
1935 J (apex)
25degres celsius has more thermal energy
15480.80
Its internal energy increses
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
1935 J (apex)
Is the amount of energy that is required to change the temperature of 1kg of a substance by 1 degree Celsius with no state change.
80cal/g
You will lose thermal energy.Heat (energy) will always flow from warmer to cooler.