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3.50 J
1935 J (apex)
15480.80
1935 J (apex)
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
3.50 J
1935 J (apex)
15480.80
25degres celsius has more thermal energy
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
1935 J (apex)
false its 1 degrees Celsius
80cal/g
You will lose thermal energy.Heat (energy) will always flow from warmer to cooler.
Kelvin is a measure of temperature or thermodynamic energy, and is an absolute measure. Degrees Celsius are a used to measure temperature on a scale with an arbitrary zero.
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
The energy required to raise the temperature 1 degree Celsius of 1 gram of water (1 mL) is 1 calorie (=4.18 J). So for 1 kg, 1Kcal (= 4180 J = 4.18 KJ) is required. To raise it 60 degrees, just multiply by 60 and for 10 kg multiply by 10 again. That would make 2.508 MJ (= 2508000 J) Now this is not completely accurate. The energy required to raise the temperature of water differs at 20 degrees from that at 60 degrees. The difference is small (~0.05 J or something like that) but still present.