The answer is actually partially dependent on the starting temperature of the water (heat capacity is a function of temperature). You will still be close enough for most purposes if you assume that it takes 1 calorie to heat 1 gram of water 1 °C. With this assumption it takes 1000 calories to heat 1 kg of water °C and 5000 calories to heat 1 kg of water 5 °C. 5000 cal = 5 kilocalories = 20929 joules.
how much energey is required its 100%
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
23joules
The simple beginning is that the definition of a calorie is "the energy required to raise the temperature of 1g of water 1°C." Therefore, the energy required to raise 17g of water 32°C: 17*32=544 cal. However, the question asked about ice. There is an extra bit of energy required for the change of physical state. The energy required to convert 1 gram of ice at 0°C to liquid water at 0°C is called the "latent heat" and is equal to about 80 cal. To convert 17g of ice, we multiply this together: 17g * 80cal/g = 1360 cal. So, we add this energy required for the change of state to the energy required to raise the listed quantity to the required temperature and we get 544 cal + 1360 cal = 1904 cal, assuming no heat is lost to the environment. I hope this clarifies some things.
Simply it's because Heat and Temperature are not interchangeable. They're not the same thing. Heat is a form of energy. Temperature is not. When heat encounters a substance, it can change the state of the substance or raise it's temperature. Temperature is only a measurement that relates to the molecules kinetic energy. But it says nothing about potential energy. Consider for a moment how much TOTAL potential heat energy is in even a bowl of warm water. You would need a lot of energy to raise a cold bowl of water to that same warm temperature? Could the candle do it? Possibly, but over a long period. That flame might be hot, but it doesn't possess the same energy? Btw: Water has a considerably high Specific Heat, which is the amount of heat (energy) required to raise it's temperature by 1 degree for 1 gram
4.184 J/g/K = 4.184 x 150 x (318-274) = 27614 Joules
Depends on how high you want to raise the gram of water ;).
No. The quantity of energy required to raise the temperature of water is different depending on the phase of water. This is especially true at or near a phase transition as thermal energy is absorbed during a phase transistion thus altering the amount of energy required to raise the temperature of said water.
4.1858 joules of energy will raise the temperature of 1 g of water by 1oC. Thus, 4.1858 * 955 * 80 = 319795.12 joules of energy is required to raise the temperature of 955 g of water by 1oC.
Energy required to raise 1 gramme of water by 1 degree C = 1 calorie also, 1 calorie = 4.186 Joules
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
15480.80
It would depend on the temperature of the water, or average kinetic energy. (KE) However, what you may be looking for is how much heat is needed to raise the KE, or temperature, of water. 4.184 kilojoules per gram is the heat required to raise the temperature of water 1 degree Celsius.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
It is harder to raise the temperature of water than it is to raise the temperature of a rock. It takes 1 calorie of energy to raise the temperature of 1 gram of water by 1 degree C, whereas it only takes 0.02 calorie to heat a gram of rock to that temperature.
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material
calories were never "made." they are simply the amount of energy required to raise the temperature one gram of water one degree celsius.