1,386J
the formula needed in q=mC Delta T
Delta is usually written as a triangle, but that not available here.
q is heat
m is mass
C is specific heat (of copper in this case) every substance has a constant
delta T means change of temp, in degrees centigrade to match units of "C"
so, calculate delta T, convert to centigrade first then plug in numbers, multiply and go. 353 K - 293K = 80 Centigrade - 20 Centigrade = 60 Centigrade
see... q = (60.00 G)(0.39J/gxdegrees centigrade)(60 C)
all units cancel out except joules, the unit of heat, 1404 Joules
1386!!
The specific heat of copper is 0.386 J/g/deg. Heat absorbed = q = mC∆T
∆T = 353º - 293º = 60 deg and m = mass = 60.00 grams
q = (60.00 g)(0.386 J/g/deg)(60 deg) = 1389.6 Joules (1390 J with 3 sig figs)
q = mC∆T where q is heat; m is mass; C is specific heat of Cu; ∆T is change in temperature.
q = (60g)(0.385 J/g/deg)(60 deg) = 2466 J (joules). Note: you need to look up the C for Copper.
This heat is 1,386 kJ.
1386j
1,386 J
There shouldn't be any copper in eight grams of gold! Unless it's a copper/gold alloy.
431.5 grams
1654 grams exactly
What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?
The easiest way to solve these problems is to use what is called a unit multiplier. First begin with the number of grams of copper that you have, then use the unit multiplier that expresses the number of grams per mole of copper (this is the number that corresponds to the atomic mass on the periodic table times grams, divided by moles). Then use the number of copper atoms that it takes to create copper oxide; this will depend on the oxidation state of the copper. Finally it reverse the process by adding up the atomic masses of copper oxide, and that will be the number of grams per mole of copper oxide, returning you from Moles back to Grams.
There shouldn't be any copper in eight grams of gold! Unless it's a copper/gold alloy.
431.5 grams
Those are 95 percent copper. A US penny weighs 3.11 grams. Of that, 2.9545 grams is copper.
10 grams of copper can kill you. But copper sulphate won't kill you. So don't freak out!
35 grams X 80 dollars/ 14 grams = 200. The cost of 35 grams of copper would cost $200 according to the given information.
1654 grams exactly
You need to multiply the volume, by the density of copper.
About 150.2 grams of Copper.
Exactly 33,13035046 grams of copper.
What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?
431.5 grams A+LS =^.^=
The easiest way to solve these problems is to use what is called a unit multiplier. First begin with the number of grams of copper that you have, then use the unit multiplier that expresses the number of grams per mole of copper (this is the number that corresponds to the atomic mass on the periodic table times grams, divided by moles). Then use the number of copper atoms that it takes to create copper oxide; this will depend on the oxidation state of the copper. Finally it reverse the process by adding up the atomic masses of copper oxide, and that will be the number of grams per mole of copper oxide, returning you from Moles back to Grams.