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0.450 kg = 450 grams

q = mass * specific heat * change in temp.

q = (450 grams)(4.180 J/gC)(20 C - 35C)

= - 2.8 X 10^4 Joules of heat lost

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Q: How much heat is lost by water as 0.250kg cools from 35 degrees Celsius to 20 degrees Celsius?
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