41,800
none
The necessary heat is 9,22 joules.
It requires 1 calorie to increase 1 mL of water by 1 degree Celsius. In 68 grams of water, there are 68 mL. The change in temperature is 7 degrees, so 476 calories are needed. 1 calorie has 4.184 joules, hence 1.992 kJ are needed.
1oo calories for 1 g
19.7 kJ
how much heat is required to convert 0,3kg of ice at 0c to water at the same tempture
none
The specific heat of water determines how much energy is needed to heat water.
The needed heat is 2 258 kJ.
53 mL water must be added.
It depends on how much it needs to be cooled down, or transferred. The more heat there is the more coolant (water) is needed.
The molar heat of fusion of water in J / g is 334. To find the heat required to convert 0.3 kg, use the equation: heat of fusion * mass = heat required. It would require 100.2 kJ.
The necessary heat is 9,22 joules.
It would depend on the temperature of the water, or average kinetic energy. (KE) However, what you may be looking for is how much heat is needed to raise the KE, or temperature, of water. 4.184 kilojoules per gram is the heat required to raise the temperature of water 1 degree Celsius.
2,641,760J...
7.9
It requires 1 calorie to increase 1 mL of water by 1 degree Celsius. In 68 grams of water, there are 68 mL. The change in temperature is 7 degrees, so 476 calories are needed. 1 calorie has 4.184 joules, hence 1.992 kJ are needed.