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How much heat is needed to warm 250 g of water from 22 c to near 98c?
Wiki User
∙ 9y ago
I think you should try and use
q = mcT
where q = heat change
m = mass of substance
c = specific heat capacity of the substance ( Water is 4.187 kJmol-1)
T = change in temperature (oC)
so for your question,
q = mcT
q = 12 x 4.187 x (93-15.4)
q = 3898.9344 kJmol-1
Hope this helps!!
Wiki User
∙ 14y ago
Wiki User
∙ 13y agoUse this formula.
q(in Joules) = mass * specific heat water * change in temperature
q = nCT
q = (46.3 grams H2O)(4.180 J/gC)[90.4 C - (-23.0 C)]
= 21947 Joules
2.19 X 10^4 Joules ( significant figures )
Wiki User
∙ 11y agoI don't know chemistry is bs your better of doing better things then this garbage
Wiki User
∙ 9y agoIn calories it's the mass times the temperature rise, so 250 x 76 or 19000 calories.
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