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100
The idea here is to multiply the force by the distance.
The work done is stored as potential energy of the box P=Mgh F=Ma (a=g) F=Mg h=5m Therefore the work done is 20*5 = 100 joules -----------------------------------------------------------------------------------------------------
m g h = (5.00) x (9.8) x (0.75) = 36.75 newton-meters = 36.75 joules, with respect to the floor.
2,088 J
100
The idea here is to multiply the force by the distance.
100
The work done is stored as potential energy of the box P=Mgh F=Ma (a=g) F=Mg h=5m Therefore the work done is 20*5 = 100 joules -----------------------------------------------------------------------------------------------------
980 w=m x g x d
m g h = (5.00) x (9.8) x (0.75) = 36.75 newton-meters = 36.75 joules, with respect to the floor.
2,088 J
We must assume that the force pushes parallel to the floor.Work = (force) x (distance) = (800) x (1.5) = 1,200 newton-meters = 1,200 joules
The potential energy is 147 joules.
If the 25N force is directed straight up, so that the force itself moves 1.5 meters tofinish the job, then it does 37.5 joules of work, which becomes 37.5 more joules ofgravitational potential energy that the plant has, once it's on the shelf.
Just use the basic definition of work:work = force x distanceIf the distance is in meters and the force is in newton, then the work will be in joules.
Work= 200 Joules.