200 kg @ max load capacity of 85% = 306 Litres
The heating value of the LPG is about 46 MJ/kg.
The specific gravity of gasoline is approximately 0.701150 kg/min * (m^3/0.70*10^3 kg) * (1000 L /m^3) * (1 min / 60s) = 27 L / s
Of course it depends on the target pressure and temperature, so I don't have an exact answer, but I can show you how to make a good guess can form the density of liquid propane and the ideal gas law. The density of the liquid material at average sea-level atmospheric pressure and at its boiling temperature I have looked up and found to be 582 kg/m3. The gas at 25 C and average sea-level atmospheric pressure has a density of (moles*Molecular weight)/Volume = (Pressure*molecular weight)/(ideal gas constant*absolute temperature). Pressure = 1 atmosphere Molecular weight = 0.0441 kg/mole Ideal gas constant = [0.00008206 M3 Atm / K] Absolute temperature = 298.15 (i.e., 25 C) or density = 1 Atm * 0.0441 kg/mole / (0.00008206 M3 Atm /K * 298.15 K) = 1.8025 Kg/M3 Literature seems to say 1.8324 Kg/M3 (which is the same as g/L). This is simply because the ideal gas law is only an approximation -- this gas is close to it liquefaction point, so it is showing some discrepancy from ideal behavior. The expansion Ratio to get to standard conditions is therefore close to 582/1.80, or ~320
Note: edited for correctness Assuming that you meant ppmw (parts per million by weight), and not ppmv (parts per million by volume); and also that you meant short tons (2000 lbs) and not metric tonnes (1000 kg): x /(500 tons * 2000 lbs/ton + x) = 6/1,000,000 Where x is the amount of odorant in pounds. Solving for x yields: x= 6.000036 lbs for a 6 ppmw (parts per million weight) concentration This shows we can neglect the amount of odorant added since it is insignificant (0.00036 lbs) in the total, and the equation reduces to: x/(500*2000) = 6x10-6 yielding: x=6 lbs for 6ppmw likewise: x=12.001 lbs of odorant for 12ppmw or x=12 lbs for the simple calculation. Important conversion: ppm/1x106= fraction in total
1.823kj/kg
1270 Liter Methane is equal to One KG LPG
its depends on the temperature and the density which is never constant , but still one kg = 1.65 lt of lpg
2.6 Kg of CO2
How many nm3 of lpg makes 1 kg of lpg
10 000
How many kg in aliter of lpg
It is 28.316 lts of LPG.
Specific gravity of LPG is 54 kg/liter.
1 Kg of LPG = 1.98 liter
1.83 l
The heating value of the LPG is about 46 MJ/kg.
27.03 mm^3 of air