First we start with a constant. At STP (273 K, 1 atm), 1 mole of gas occupies 22.4L or 0.0224 m3.
So then we use V1/T1 = V2/T2 with temperature in Kelvin.
0.0224 m3 / 273 K = V2 / 373 K (I am going to assume that the steam is not superheated, and remains at 100 C or 373 K)
Multiply 373 K to both sides of the above equation, and we get: V2 = 0.0306 m3
Now that I have calculated that 1 mole of steam (or any gas at 100 C) takes up 0.0306 m3 of volume, I can find how many moles of steam occupy 1 m3.
1 m3 / (0.0306 m3/mole) = 32.7 moles
Since you asked how many m3 of water corresponds to 1 m3 steam, we must then convert our 32.7 moles of H2O into a volume. This require the use of two additional constants: the molar mass, and density of water.
The molar mass of water is approx. 18 g/mole. The density of water is 1 g/cm3.
Our cubic meter of steam weighs: 32.7 moles * 18 g/mole = 588.1 g
And so this amount of steam, when condensed, occupies 588.1 cm3.
Finally, we multiply this quantity by a conversion factor (1 = 10-6 m3 / 1 cm3) to obtain the result in m3.
588.1 cm3 * (10^-6 m3 / 1 cm3) = 0.000588 m3, or 5.88*10-4 m3
75 m3 of natural gas.
1750 ft3 is equal to 49.55 m3.
2.7 m3 (2,700 liters) if the aluminum is at room temperature
g / cm3 * 1000 = kg / m3
( 1 m3 ) x ( 100 cm/m )3 = (100)3 ( m3 cm3 / m3 ) = 106 cm3 = 1,000,000 mL
75 m3 of natural gas.
1 M3 of water will make 1 tomme of steam
for converting cubic meter to ton , density or specific volume is needed. specific volume unite is m3/kg. steam cubic meter/ (cubic meter/kg)= steam (kg ) /1000= tone of steam
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