B4O7^2- + 7H2O = 4H3BO3 + 2OH-
B4O7^2- : 2OH- = 1:2
Therefore there are twice the number of moles of Hydroxide ions produced as there are Borate ions
0.76 mole
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
2 moles of Ca and 4 moles of OH
In the combustion of C7H16, 7 moles of O2 are required to form 8 moles of CO2. From the given 19.4g of CO2, 1 mole of CO2 is equivalent to 44g. Using stoichiometry, we can calculate that 25.23g of O2 are consumed during the combustion.
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
To calculate the number of moles in 20g of borax (Na2B4O7), we first need to find the molar mass of borax. By adding the atomic masses of all the elements in borax, we get a molar mass of approximately 201.22 g/mol. Then, we use the formula: moles = mass / molar mass. Substituting in the values, we find that there are approximately 0.10 moles of borax in 20g. Since there are four boron atoms in one molecule of borax, the number of moles of B (boron) would be 0.10 moles * 4 = 0.40 moles.
No, moles are not true hibernators in the winter. Moles are capable of entering torpor which preserves energy and allows the moles to rest during cold weather.
0.76 mole
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
B4O5(OH)4^2- there are four boron atoms in borax the molecular weight of boron is 10.811g/mol to convert to molecules -> moles times avagadro's number (6.023 x 10^23) ->> 4 x 6.023 x 6.023 x 10^23 = 2.4092 x 10^24 (you can carry it to this many significant figures because 4 and avagadro's number [6.023 x 10^23] are exact/absolute number)
Na2B4O7 + H2SO4 = H3BO3 + Na2SO4This unbalanced equation is given in my chemistry book (Zumdahl World of Chemistry) and we are supposed to balance it in order to find the mole ratios.Every resource I have used says this equation is impossible to balance.The answers in Zumdahl imply that there is a ratio of 1 mol borax to 4 moles boric acid, and 1 mol borax to 1 mol sodium sulfate, but no coefficients are ever given.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
this is a easy one. There are only 0.04166 moles.
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
The mole ratio to convert from moles of a to moles of b is determined by the coefficients of a and b in the balanced chemical equation. For example, if the balanced equation is 2A + 3B -> 4C, the mole ratio would be 3 moles of B for every 2 moles of A.
2 moles of Ca and 4 moles of OH
For every mole of methyl alcohol (CH3OH) that is combusted, one mole of CO2 and two moles of water are produced. Therefore, if 3.25 moles of CO2 are formed, this means 3.25 moles of methyl alcohol were combusted, leading to the production of 6.5 moles of water (2 moles of water for every mole of CH3OH).