For each isotope of Hs the number of neutrons is different. Number of neutrons = Mass number of an Hs isotope – 108
$225,000 - $375,000
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It is no big deal. You could do that if the die was not the standard cube with numbers 1 to 6.
LF - album - was created on 2011-07-22.
It's not pretty (because I've never written anything in C before but it worked nonetheless) but here you go. I compiled with Microsoft Visual C++ 2010 Express with a Win32 Console Application and this is everything that was written. It worked but looks kind of bulky. Tweak to your heart's content. I wasn't 100% sure what you wanted so I made three versions that do basically the same thing with slight alterations. I learned to code in C for you... This one lists each one that was either positive or negative. // snfp.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include "stdio.h" int main (void) { /* declarations */ double x0=0, x1=0, x2=0, x3=0, x4=0, x5=0, x6=0, x7=0, x8=0, x9=0, y0=0, y1=0, y2=0, y3=0, y4=0, y5=0, y6=0, y7=0, y8=0, y9=0, z0=0, z1=0, z2=0, z3=0, z4=0, z5=0, z6=0, z7=0, z8=0, z9=0; /* executable statements */ printf ("Enter ten real numbers: "); scanf ("%lf %lf %lf %lf %lf %lf %lf %lf %lf %lf", &x0, &x1, &x2, &x3, &x4, &x5, &x6, &x7, &x8, &x9); if(x0<0){ y0 = x0;} if(x0>0){ z0 = x0;} if(x1<0){ y1 = x1;} if(x1>0){ z1 = x1;} if(x2<0){ y2 = x2;} if(x2>0){ z2 = x2;} if(x3<0){ y3 = x3;} if(x3>0){ z3 = x3;} if(x4<0){ y4 = x4;} if(x4>0){ z4 = x4;} if(x5<0){ y5 = x5;} if(x5>0){ z5 = x5;} if(x6<0){ y6 = x6;} if(x6>0){ z6 = x6;} if(x7<0){ y7 = x7;} if(x7>0){ z7 = x7;} if(x8<0){ y8 = x8;} if(x8>0){ z8 = x8;} if(x9<0){ y9 = x9;} if(x9>0){ z9 = x9;} printf ("\nThe negative numbers are %lf %lf %lf %lf %lf %lf %lf %lf %lf %lf.\n", y0, y1, y2, y3, y4, y5, y6, y7, y8, y9); printf ("\nThe positive number are %lf %lf %lf %lf %lf %lf %lf %lf %lf %lf.\n", z0, z1, z2, z3, z4, z5, z6, z7, z8, z9); printf ("Type something to exit"); scanf ("%lf", &x0); return (0); } This one tells you how many were positive and how many were negative. // snfp.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include "stdio.h" int main (void) { /* declarations */ double x0=0, x1=0, x2=0, x3=0, x4=0, x5=0, x6=0, x7=0, x8=0, x9=0, y0=0, y1=0, y2=0, y3=0, y4=0, y5=0, y6=0, y7=0, y8=0, y9=0, z0=0, z1=0, z2=0, z3=0, z4=0, z5=0, z6=0, z7=0, z8=0, z9=0, neg=0, pos=0; /* executable statements */ printf ("Enter ten real numbers: "); scanf ("%lf %lf %lf %lf %lf %lf %lf %lf %lf %lf", &x0, &x1, &x2, &x3, &x4, &x5, &x6, &x7, &x8, &x9); if(x0<0){ y0 = 1;} if(x0>0){ z0 = 1;} if(x1<0){ y1 = 1;} if(x1>0){ z1 = 1;} if(x2<0){ y2 = 1;} if(x2>0){ z2 = 1;} if(x3<0){ y3 = 1;} if(x3>0){ z3 = 1;} if(x4<0){ y4 = 1;} if(x4>0){ z4 = 1;} if(x5<0){ y5 = 1;} if(x5>0){ z5 = 1;} if(x6<0){ y6 = 1;} if(x6>0){ z6 = 1;} if(x7<0){ y7 = 1;} if(x7>0){ z7 = 1;} if(x8<0){ y8 = 1;} if(x8>0){ z8 = 1;} if(x9<0){ y9 = 1;} if(x9>0){ z9 = 1;} neg = y0 + y1 + y2 + y3 + y4 + y5 + y6 + y7 + y8 + y9; pos = z0 + z1 + z2 + z3 + z4 + z5 + z6 + z7 + z8 + z9; printf ("\nThere are %lf negative numbers.\n", neg); printf ("\nThere are %lf positive numbers.\n", pos); printf ("Type something to exit"); scanf ("%lf", &x0); return (0); } This one sums the positive and then sums the negative. // snfp.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include "stdio.h" int main (void) { /* declarations */ double x0=0, x1=0, x2=0, x3=0, x4=0, x5=0, x6=0, x7=0, x8=0, x9=0, y0=0, y1=0, y2=0, y3=0, y4=0, y5=0, y6=0, y7=0, y8=0, y9=0, z0=0, z1=0, z2=0, z3=0, z4=0, z5=0, z6=0, z7=0, z8=0, z9=0, neg=0, pos=0; /* executable statements */ printf ("Enter ten real numbers: "); scanf ("%lf %lf %lf %lf %lf %lf %lf %lf %lf %lf", &x0, &x1, &x2, &x3, &x4, &x5, &x6, &x7, &x8, &x9); if(x0<0){ y0 = x0;} if(x0>0){ z0 = x0;} if(x1<0){ y1 = x1;} if(x1>0){ z1 = x1;} if(x2<0){ y2 = x2;} if(x2>0){ z2 = x2;} if(x3<0){ y3 = x3;} if(x3>0){ z3 = x3;} if(x4<0){ y4 = x4;} if(x4>0){ z4 = x4;} if(x5<0){ y5 = x5;} if(x5>0){ z5 = x5;} if(x6<0){ y6 = x6;} if(x6>0){ z6 = x6;} if(x7<0){ y7 = x7;} if(x7>0){ z7 = x7;} if(x8<0){ y8 = x8;} if(x8>0){ z8 = x8;} if(x9<0){ y9 = x9;} if(x9>0){ z9 = x9;} neg = y0 + y1 + y2 + y3 + y4 + y5 + y6 + y7 + y8 + y9; pos = z0 + z1 + z2 + z3 + z4 + z5 + z6 + z7 + z8 + z9; printf ("\nThe negative numbers add up to %lf.\n", neg); printf ("\nThe positive number add up to %lf.\n", pos); printf ("Type something to exit"); scanf ("%lf", &x0); return (0); }
..use do{} while{}..for example..#includemain(){int choose;double a,b,c;printf("Enter 7 if you want to use the calculator. Otherwise,type any character.\n");scanf("%d",&choose);do{if (choose==7){printf("Press 1 for addition.\n");printf("Press 2 for subtraction.\n");printf("Press 3 for multiplication.\n");printf("Press 4 for division.\n");scanf("%d",&choose);if (choose==1){printf("Enter the addends\n");scanf("%lf %lf", &a,&b);c=a+b,printf("The sum of %lf and %lf is %lf.\n",a,b,c);}else if(choose==2){printf("Enter the minuend and subtrahend\n");scanf("%lf %lf", &a,&b);c=a-b,printf("The difference of %lf and %lf is %lf.\n",a,b,c);}else if(choose==3){printf("Enter the multipliers\n");scanf("%lf %lf", &a,&b);c=a*b,printf("The product of %lf and %lf is %lf.\n",a,b,c);}else if(choose==4){printf("Enter the dividend and divisor\n");scanf("%lf %lf", &a,&b);c=a/b,printf("The quotient of %lf and %lf is %lf.\n",a,b,c);}else{printf("You have entered an invalid digit.\n");}printf("If you want to continue,press 7 and choose again from 1 to 4.\n");printf("Do you want to exit? Enter any key.\n");scanf("%d",&choose);}}while(choose==7);}
What does LF on cabrio washer mean
pounds of force LF is a measurement for FIBERCLASS CLOTH, so Linear Foot(LF) is probably more in line with this product. LF is also a measure for Leaf. One Leaf = One Sheet, or One Piece
Leapfrog Enterprises Inc (LF)had its IPO in 2002.
depending on condition anywhere from $350 up $$$$
LF typically stands for Line Feed, which is a control character that advances the printing position to the next line on a display or printer. In computing, LF is used in text files to denote the end of a line.
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