25 g
Explanation:Think about what a nuclear half-liferepresents, i.e. the time needed for an initial sample of a radioactive substance to be halved.
The number of days is 96,4.
The mass is 1,075 g.
8.1 days is, if half-life is 2.7 days, 3 half-lives. 12.5%, or 12.5 g, of 79198Au would remain after three half-lives.
The half life is the time it takes for half the atoms in a given sample to decompose. Knowing this then after 27 days there is half the amount left. After 54 days then there is half that half left so that's a quarter.
The time required for a 6.95 sample to decay to 0.850 if it has a half-life of 27.8 days is 255 days/ Radioactive decay is based on half-lifes, specifically the reciprocols of powers of 2. The equation for decay is... AN = A0 2(-N/H), where A is activity, N is number of half lives, and H is half life. Calculating for the question at hand... 0.850 = 6.95 2(-N/27.8) 0.122 = 2(-N/27.8) log2(0.122) = -N/27.8 -3.04 = -N/27.8 N = 9.16, or TN = (9.16) (27.8) = 255
Thorium-234 has a half-life of 24.1 days. How much of a 100-g sample of thorium-234 will be unchanged after 48.2 days?
After 48,2 days the amount of Th-234 will be 25 g.
After 48,2 days the amount of Th-234 will be 25 g.
After 9 days, the population of ladybugs would double every 3 days, so it would double 3 times. 2^3 = 8. Therefore, the population at the end of 9 days would be 30 ladybugs x 8 = 240 ladybugs.
18 days
5.0 mg is the total mass of 222Rn remaining in an original 160-milligram sample of 222Rn after 19.1 days.
18 grams are one fourth of the original sample mass of 72 grams. Accordingly, the half life is 6.2/4 = 1.55 days.
The number of days is 96,4.
50 days the solution goes thus 100g/2 = 50 days
10.76 days
The answer depends on 3240 WHAT: seconds, days, years?
A urine sample usually lasts up to 7 days if frozen.