The power to propel a ship is dependent on a number of things besides resistance. You must consider the size of the ship, its weight, and its passenger's weight before you can determine the power required to move it.
power=i square*resistance or power=v suare/resistance
Since power = voltage2/resistance, reducing the resistance will increase the power of the circuit. Incidentally, power is not 'consumed'; it's energy that's consumed.
Power=current squared times resistance
It will decrease the effective load resistance across the power supply terminals, increase the total current through the load, and increase the total power required to be supplied by the power supply.
I never measured the resistance of an electric iron, but: the 15 ohm resistance is probably required to develop a required 806 watts of power. Using Ohm's law, I(current) = E(voltage)/R(resistance), therefore I(current) =110 volts/15 ohms = 7.33 Amps (current), and, Power (watts) = E(voltage) X I(current); 110 volts X 7.33 amps = 806 watts. The iron requires that wattage to develop enough heat in the sole of the iron. Hope this helps.
If you ar referring to the power transfer equation, P = V1*V2/Z, it should be considered in Z, but often the resistance component is small so it can be neglected without serious error.
The length ,thickness, and alloy of the filament determines its resistance. The lower the resistance, the lower the voltage required to power it.
power=i square*resistance or power=v suare/resistance
So that there's a power source to propel the vehicle.
Thrust is the power made by a jet engine to propel an aircraft.
Since power = voltage2/resistance, reducing the resistance will increase the power of the circuit. Incidentally, power is not 'consumed'; it's energy that's consumed.
Power=current squared times resistance
Power is inversely proportional to resistance. Ohm's law: Current is voltage divided by resistance Power law: Power is voltage times current, therefore power is voltage squared divided by resistance.
All resistances will emit heat energy when a current flows. The heat production rate (or power) can be found by any of these formulas: Power = Current * Voltage Power = Current2 * Resistance Power = Voltage2 / Resistance. Power is given in Watts when Current is in Amps, Voltage in Volts, and Resistance in Ohms.
yes, batteries have high internal resistance. The higher the resistance the lower power you get out of the batter. Therefore if you no power you have very high resistance.
It will decrease the effective load resistance across the power supply terminals, increase the total current through the load, and increase the total power required to be supplied by the power supply.
I never measured the resistance of an electric iron, but: the 15 ohm resistance is probably required to develop a required 806 watts of power. Using Ohm's law, I(current) = E(voltage)/R(resistance), therefore I(current) =110 volts/15 ohms = 7.33 Amps (current), and, Power (watts) = E(voltage) X I(current); 110 volts X 7.33 amps = 806 watts. The iron requires that wattage to develop enough heat in the sole of the iron. Hope this helps.