If you ar referring to the power transfer equation, P = V1*V2/Z, it should be considered in Z, but often the resistance component is small so it can be neglected without serious error.
The formula for calculating the power dissipated in a resistor, known as the i2r power, is P I2 R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms.
As the name implies, resistance resists current. In the mathematical formula, where E is electromotive force (voltage):- I = E/R If you increase the value of R (resistance), then the value of I (current) decreases.
Power dissipation in a conductor is given by the formula ( P = I^2 R ), where ( P ) is power, ( I ) is the electric current, and ( R ) is the resistance. If the electric current is doubled, the new current becomes ( 2I ). Substituting this into the power formula results in ( P' = (2I)^2 R = 4I^2 R ), which shows that the power dissipation increases by a factor of four. Therefore, doubling the current through a constant resistance results in a fourfold increase in power dissipation.
Below 5 ohms
Equivalent resistance of a series circuit is the sum of the resistance of all appliances. The formula is R=R1+R2+... where R is equivalent resistance, R1, R2 and so on is the resistance of the individual appliances.
No. there are many different power ratings for the same resistance. Type your answer here...
0.1~10
To determine the correct resistance, you need to consider the specific application or circuit in question, including the voltage, current, and the desired power dissipation. Use Ohm's Law (V = IR) to calculate resistance (R = V/I). Additionally, ensure that the resistor can handle the power rating (P = IV) without overheating. Always refer to the circuit requirements or specifications for the most accurate value.
The resistance value of a 1 meter copper wire depends on its gauge (thickness) and temperature. For example, a 1 meter wire of 24-gauge copper has a resistance of about 25.67 ohms at room temperature. It is important to consider these factors when calculating the resistance of copper wire.
the power will be reduced to the haflf because P=V2/R so when the resistance doubles the power reduced to the half of itsoriginal value
Roughly 36 kilowatts.
You have to convert the peak voltage to an r.m.s. value, before inserting that value into the power equation.