Equivalent resistance of a series circuit is the sum of the resistance of all appliances. The formula is R=R1+R2+... where R is equivalent resistance, R1, R2 and so on is the resistance of the individual appliances.
The formula you are looking for is Ohms = Volts/Amps. R = E/I.
Taking some bulbs out of the circuit!! (I think :P) Taking some bulbs out of the circuit!! (I think :P) Use Ohm's law I = E/R. Add some values and check it out. You use the formula V = IR (where V and E are the same thing, voltage. I is the current. R is the resistance). If you add more resistance then your current will be lower. I would suggest looking at parallel and series resistance so that you can understand equivalent resistance.
Adding a resistance in parallel to another resistance will reduce the equivalent resistance. Parallel Equation: R1 = 10Ω R2 = 20Ω Req = R1R2/(R1+R2) = (1/R1+1/R2)-1 Req = 10•20/(10+20) = 6.67Ω
For DC circuits: R = l*p / A R - resistance l = length of the conductor p = electrical resistivity A = the cross sectional area Calculating for AC, and especially three phase power becomes much more complicated. If you need to know more for AC, let me know specifics.
what is the formula for calculating volume of preesure vessels with dishe ends
The formula for calculating resistance in an electrical circuit is R V/I, where R is the resistance, V is the voltage, and I is the current.
The formula for calculating current in a circuit when given the values of power and resistance is i p/a.
The formula for calculating the resistance of a capacitor in an electrical circuit is R 1 / (2 f C), where R is the resistance, f is the frequency of the circuit, and C is the capacitance of the capacitor.
The formula for calculating the maximum voltage in an electrical circuit is V I R, where V is the voltage, I is the current, and R is the resistance.
The formula for calculating power loss in a circuit is P i2 R, where P represents power loss, i is the current flowing through the circuit, and R is the resistance of the circuit.
The formula for calculating power in a circuit using the keyword "power i 2r" is P I2 R, where P represents power, I represents current, and R represents resistance.
RSeries = SummationI=1toN (RI) Simple answer; add them up.
To calculate the equivalent resistance in a parallel circuit, you use the formula: 1/Req 1/R1 1/R2 1/R3 ... 1/Rn, where Req is the equivalent resistance and R1, R2, R3, etc. are the individual resistances in the circuit.
To determine the equivalent resistance in a parallel circuit, you can use the formula: 1/Req 1/R1 1/R2 1/R3 ... 1/Rn, where Req is the equivalent resistance and R1, R2, R3, etc. are the individual resistances in the circuit.
The formula for calculating the resistance of a capacitor is R 1 / (2 f C), where R is the resistance in ohms, f is the frequency in hertz, and C is the capacitance in farads.
No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.
In a complex circuit with various elements (resistors, capacitors etc.) and one battery, the various circut elements contribute to draw a certain amount of current "I"from the battery at some terminal voltage "V". The "equivalent" resistance of the various circuit elements is that resistance "R" which will draw the same current , at the same terminal voltage, as the complex circuit. So to find "R" you simply imagine replacing the complex circuit with "R" by attaching "R" across the terminals of the battery and use Ohms law to find "R" , demanding "I" and "V" are the same. So then R = V/I.