As the name implies, resistance resists current. In the mathematical formula, where E is electromotive force (voltage):- I = E/R If you increase the value of R (resistance), then the value of I (current) decreases.
Because of power losses.
Load current is related to load resistance by an inverse relationship. The load current increases linearly as load resistance decreases. Remember, the less resistance, the more current.
yes
The current in a short circuit may be very high because the resistance in the short circuit is probably less than the resistance in the original circuit.
Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.
An ammeter has to measure to current flowing through the circuit. Resistance offers an obstruction to the current flow. So, if the resistance of an ammeter is large , the current measured by the ammeter will be quite less as compared to the actual amount of current flowing through the circuit which is undesirable. If ammeter has zero resistance , then it will give the exact value of current. But this is not practically possible because every material has some value of internal resistance which we can't control. For this reason , ammeter must have small resistance
Because the meter is actually measuring the current through the resistor, and the two quantities ... current and resistance ... are inversely proportional. So when the meter measures more current, it has to read less resistance, whereas higher resistance will result in less current. So the numbers for resistance have to be printed "backwards" on the meter scale.
Load current is related to load resistance by an inverse relationship. The load current increases linearly as load resistance decreases. Remember, the less resistance, the more current.
Absolutely the more Resistance is put in series the less current Will flow.
The higher the resistance, the less current will flow through it (while the supply voltage remains constant).
The resistance in the start winding is greater because it is longer and thinner and has the greatest resistance to current flow
The law named after him is: V = IR (in words: voltage = current x resistance) It is more intuitive if you express it solved for current, since current can be thought of as the dependent variable: I = V/R This shows that more voltage will result in more current, while more resistance will result in less current. Of course, in the SI the units are chosen in such a way that the proportionality constant is one (and doesn't appear in the equation).
The higher the resistance the less current can pass through therefore the current will be lower.
A resistor's resistance is measured in ohms. The higher the resistance the less current will flow with a constant voltage applied across the resistor. In terms of Ohm's Law Voltage = Current x Resistance.
The only limit on how much current the conductor can carry, regardless ofthe weather, is the amount of current that causes the conductor to melt.The current in such a conductor depends on the voltage between its ends,and on the resistance of the conductor. The resistance of the conductor issomewhat less when it's cold, so a given voltage would result in more current.
Ohm's Law: V = IR Solving for current: I = V/R To affect the current, you can either change the voltage (more voltage --> more current), or the resistance (more resistance --> less current).
The ohm is the unit of electrical resistance to current flow. More ohms (more resistance), the less current will flow. Less ohms (less resistance), the more current will flow. One ohm is defined as the amount of resistance that will cause one ampere of current to flow if the supply voltage is one volt. Ohm's law states that amps = volts / ohms So, if you had a 12 volt battery, and you connected a load, say a heating element that had a resistance of 3 ohms, how much current would flow in the circuit? amps = 12 volts / 3 ohms amps = 4
A lamp with a thick filament will draw more current. What restricts the current flow in the filament is the resistance of the filament which increases as the temperature of the filament increases. A thin filament requires less energy to get heated up that a thick one so less current to achieve threshold resistance. Also a thick filament provides a broader path for current so there is less resistance per increase in degree centigrade. For these two (closely related but distinct) reasons it will require more current for the filament to get heated up to threshold resistance.