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Absolutely the more Resistance is put in series the less current Will flow.

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Q: Does current change in a circuit having bulb in series with a resistance?
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Why should you never measure resistance in a circuit carrying a current?

Ideally true, but seldom so. The vast majority of resistance meters use current to measure resistance and just use V=IR to give R - the resistor is in a circuit carrying current. The only method that does not have a current through the resistance, it actually relies on the fact, is a Wheatstone bridge. The most important reason for not having a current is that you will be using a current in most cases, to meaure the resistance. Current from another source will screw the reading. Also, with a current flowing, you are not measuring resistance - you are measuring impedance - a combination of inductance and resistance.


How do you know an electrical circuit has a short in it?

A short circuit is determined by a low resistance between two conductors or between a conductor and the ground. <<>> The circuit's over current protection usually trips resulting in the circuit having no power.


What will happen if a voltmeter has a low shunt resistance instead of having high shunt resistance?

The purpose of a voltmeter is to indicate the potential difference between two points in a circuit.When a voltmeter is connected across a circuit, it shunts the circuit. If the voltmeter has a low resistance,it will draw a substantial amount of current. This action lowers the effective resistance of the circuit andchanges the voltage reading.


What blocks current flow?

Resistors "resist" current flow. The ultimate "blocking" resistor is an open circuit, having a resistance of infinity (for all practical purposes) ohms.Capacitors also resist a change in voltage drop. For the case of a DC circuit, a capacitor, after reaching equilibrium, will present a DC resistance of infinity. For the case of the AC circuit, a capacitor will allow the AC signal to pass, while blocking any DC bias that might be present.So, resistors and, in the DC case, capacitors, block current flow.


Can interesting a resistor in a circuit produce an affect similar to a short circuit?

A true "short circuit" indicates that a device or conductor having essentially no measurable (by conventional ohm meters) resistance is connected across the circuit. Thus the current flow through the "short circuit" will be limited only by the conductors supplying the current to the "short circuit", and the source of the current.But as the resistance is increased, less current will flow. If the resistance is sufficiently high so as to NOT pass current in excess of that for which the supplying conductors are rated, AND the current that can be safely supplied by the power source, it then acts as an "intended load", and will not appear as a "short circuit".For example, an incandescent, 60 watt, 120 VAC light bulb, will have an operating resistance of approximately 240 ohms. Since power (in watts) in a resistive "load" is equal to the square of the RMS voltage applied, divided by the resistance (in ohms) of the "load'. The corresponding current would be only 1/2 ampere. (Current equals the applied voltage divided by the resistance).In typical home wiring, in which lighting circuits are usually protected by fuses or circuit breakers in the mains distribution box, the circuits are rate at 15 amperes. Thus the "resistance" of a 60 watt incandescent light bulb will have very little "load" on the circuit, and certainly can not be considered a "short circuit".


If the voltage is 12 volts and the resistance is 3 ohms what are the amps in this circuit?

Using Ohm's law, we can find the current (I) in a circuit where 3 ohms is the resistance (R) and 12 volts is the appllied voltage (V). [(E) means energy]I = V / R = 12 / 3 = 4 amps.Visit this link http://www.csgnetwork.com/ohmslaw2.html for making Ohm's Law calculations.


Which one of the following statements is true concerning an ac circuit that contains both resistance an inductance?

When an AC circuit contains both resistance and inductance the current and voltage will be in phase. This means having waveforms that are of the same frequency and that pass through corresponding value.


What is the current running through resistor 1?

I'm having some trouble focusing in on the schematic of the circuit.


What will happen to resistance If amperage goes down and voltage remains the same?

The correct term is 'current', not 'amperage'. The answer is that nothing will happen to the resistance. Having said that, changing the resistance will cause current to change for a fixed value of voltage.Resistance is determined by the length, cross-sectional area, and resistivity of a material. Resistivity is affected by temperature, so resistance is also therefore indirectly affected by temperature. Only by changing one of these variables will the resistance change.Since the ratio of voltage to current will tell us what the resistance of a circuit happens to be (it's not affected by that ratio) for a particular ratio, the ratio will increase (as per your question) if the resistance increases. But it's not the ratio that's affecting resistance, its the resistance affecting the ratio!


If amperage goes down and the voltage remains the same what happens to resistance?

The correct term is 'current', not 'amperage'. The answer is that nothing will happen to the resistance. Having said that, changing the resistance will cause current to change for a fixed value of voltage.Resistance is determined by the length, cross-sectional area, and resistivity of a material. Resistivity is affected by temperature, so resistance is also therefore indirectly affected by temperature. Only by changing one of these variables will the resistance change.Since the ratio of voltage to current will tell us what the resistance of a circuit happens to be (it's not affected by that ratio) for a particular ratio, the ratio will increase (as per your question) if the resistance increases. But it's not the ratio that's affecting resistance, its the resistance affecting the ratio!


What is the resistance when switch is open?

Nothing will happen to the resistance of the circuit. However, with the switch open, it will be 'seen' as having infinite resistance from the supply side.


When ohmmeter is zero?

It means you have effectively no resistance to current flow. Whether this is good or not depends on whether you WANT resistance to current flow. If you're testing a length of wire, a cable, or something like that, having your ohmmeter read zero would be good. If you're testing a motor or something else that needs to have resistance to work, having your ohmmeter read zero is bad and is called a Short Circuit.