yes
what is current capacity of 95 sqmm cable?
It depends on the length of th cable and the diameter of the copper cable used.
Since resistance is inversely proportional to the cross-sectional area of a wire, thicker the wire - lesser the resistance and vice-versa. Now, according to Joule's law of heating, H = I^2 R t; i.e. H (Heat) is directly proportional to the square of I (Current), R(Resistance) and t (time). Whereas, according to Ohm's law, V=IR; i.e. V (Potential difference) is directly proportional to I (Current) and R (Resistance) Comparing both the formulas, we can conclude that H (Heat) needs more Current; I. [H=I^2 R t] Therefore, thicker wire. Hence, the cooker needs a thicker wire while a table light needs a comparatively thinner wire.
To calculate the cable size for a 100 kW load, you would need to consider factors such as the voltage of the system, the type of cable insulation, the ambient temperature, and the installation method. The cable size is typically determined by the maximum current the cable will carry without overheating. Using the formula: Cable size (mm²) = (2 x L x I x R) / (√3 x V x cosΦ), where L is the cable length, I is the load current, R is the resistance of the cable, V is the voltage, and cosΦ is the power factor, you can calculate the appropriate cable size for the 100 kW load.
This is a class of current transformers, and is a fairly low class. This has to do with what kind of burden can be placed on the secondary. A general rule is a C200 current transformer can supply ~200 volts at full ratio to its' secondary. If the burden (the CT resistance + cable resistance + relay or instrument resistance) times the maximum expected current is higher than 200 volts, the CT is likely to saturate. During multiple fault events, a CT may keep some magnetizing current causing CT saturation to be higher on a reclose event. Typically CT's are sized and their ratios are chosen to minimize saturation when feasible.
Low current will equal low power losses due to the resistance of the cable. I squared R. (I is transmission current and R is resistance/Metre of cable) by increasing the voltage for the same amount of power the current decreases. Power transmission will take that advantage to transfer less current for the same amount of power.
Yes, if the cable is cracked and swollen it has a high resistance thus causing a loss of current. Replace any cracked or swollen cable.
With a constant voltage and increase in wire length will increase the end to end resistance and therefore the current will decrease.
WARNING: VERY simplified answer. An electric current will run through the most easiest path trying to get to the ground. If the easiest path is a person, the current will run through the person and cause varying amounts of harm. If the easiest path is a simple cable running straight into the ground, the current will run through the cable. Humans have a higher resistance than cables, so the easiest path is through the cable. Or perhaps another cable made of a material with even less resistance.
Because if the rated current is lower than the actual current, it causes resistance to the electrical flow which in turn is dispelled as heat.
No. Conductor resistance is. Cable insulation resistance to ground is inversely proportional to its length. The longer the cable, the more leakage path to ground; therefore, the lower the insulation resistance to ground.
Ohm's Law - V = IR.
It is done to carry more current at rated power & to reduce the power loss as compared to cable since a bus-bar has more area compared to cable so resistance is less & hence losses are reduced. It is done to carry more current at rated power & to reduce the power loss as compared to cable since a bus-bar has more area compared to cable so resistance is less & hence losses are reduced.
A ground cable may get hot due to high electrical resistance in the cable connections, excessive current flowing through the cable, or a short circuit in the electrical system. It is important to investigate and address the root cause promptly to prevent damage or fire hazards.
r=v/i=6/19.5=0.3076923077ohm, so,the resistance value must not exceed 0.4 ohm.
It is best to check with local Cable Companies to see what offers they have, they will vary state to state as well as the ones offered on their national websites and also will change over time
Conductor area refers to the cross-sectional area of a conductor, such as a wire or cable, that carries an electric current. It is typically measured in square millimeters or square inches and is an important factor in determining the current-carrying capacity and resistance of the conductor. A larger conductor area generally allows for more current to flow with lower resistance.